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Question 4[54[5 points] Consider a discrete failure time response TT, with dis...
Sep 27, 2024
Solution by Steps
step 1
To prove P(T > a_j | T > a_{j-1}) = 1 - h(a_j) , we start with the definition of conditional probability: P(AB)=P(AB)P(B) P(A | B) = \frac{P(A \cap B)}{P(B)} . Here, A A is the event T > a_j and B B is T > a_{j-1}
step 2
The event T > a_j given T > a_{j-1} implies that if the failure time is greater than aj1 a_{j-1} , it can either be greater than aj a_j or not. Thus, we can express this as: P(T > a_j | T > a_{j-1}) = 1 - P(T \leq a_j | T > a_{j-1})
step 3
The probability P(T \leq a_j | T > a_{j-1}) can be related to the hazard function h(aj) h(a_j) as P(T \leq a_j | T > a_{j-1}) = h(a_j) . Therefore, we have P(T > a_j | T > a_{j-1}) = 1 - h(a_j)
step 4
For part (b), we need to prove that S(t)=ajt[1h(aj)] S(t) = \prod_{a_j \leq t} [1 - h(a_j)] . The survival function S(t) S(t) is defined as S(t) = P(T > t) . We can express this as the product of the probabilities of surviving past each failure time aj a_j up to t t
step 5
Thus, we can write S(t) = P(T > a_1) \cdot P(T > a_2 | T > a_1) \cdots P(T > a_k | T > a_{k-1}) , where ak a_k is the largest failure time less than or equal to t t . Each term can be expressed as 1h(aj) 1 - h(a_j) . Therefore, S(t)=ajt[1h(aj)] S(t) = \prod_{a_j \leq t} [1 - h(a_j)]
step 6
For part (c), we need to prove that P(t=am)=h(am)ajam1(1h(aj)) P(t = a_m) = h(a_m) \prod_{a_j \leq a_{m-1}} (1 - h(a_j)) . The probability of the event t=am t = a_m can be expressed using the hazard function and the survival function
step 7
We can express P(t=am) P(t = a_m) as the probability of surviving up to am a_m and then failing at am a_m : P(t = a_m) = P(T > a_{m-1}) \cdot P(T \leq a_m | T > a_{m-1}) . This gives us P(t=am)=S(am1)h(am) P(t = a_m) = S(a_{m-1}) \cdot h(a_m)
step 8
Substituting S(am1)=ajam1(1h(aj)) S(a_{m-1}) = \prod_{a_j \leq a_{m-1}} (1 - h(a_j)) , we get P(t=am)=h(am)ajam1(1h(aj)) P(t = a_m) = h(a_m) \prod_{a_j \leq a_{m-1}} (1 - h(a_j))
Answer
The proofs for parts (a), (b), and (c) have been established as required.
Key Concept
The hazard function and survival function are key concepts in survival analysis, representing the instantaneous failure rate and the probability of surviving past a certain time, respectively.
Explanation
The proofs demonstrate the relationships between the survival function, hazard function, and the probabilities of failure times in a discrete failure time model.
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