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4) If AA and BB are subsets of the universal set XX and $n(X)=50, n(A)=35, \...
Jul 25, 2024
Solution by Steps
step 1
Given: n(X)=50n(X) = 50, n(A)=35n(A) = 35, n(B)=20n(B) = 20, and n(AB)=5n(A' \cap B') = 5. We need to find n(AB)n(A \cup B). Using the formula for the union of two sets: n(AB)=n(A)+n(B)n(AB)n(A \cup B) = n(A) + n(B) - n(A \cap B)
step 2
To find n(AB)n(A \cap B), we use the fact that n(AB)=n(X)n(AB)n(A' \cap B') = n(X) - n(A \cup B). Since n(AB)=5n(A' \cap B') = 5, we have n(AB)=505=45n(A \cup B) = 50 - 5 = 45
step 3
Now, we substitute n(AB)=45n(A \cup B) = 45 into the union formula: 45=35+20n(AB)45 = 35 + 20 - n(A \cap B). Solving for n(AB)n(A \cap B), we get n(AB)=10n(A \cap B) = 10
step 4
To find n(AB)n(A' \cap B), we use the formula: n(AB)=n(B)n(AB)n(A' \cap B) = n(B) - n(A \cap B). Substituting the values, we get n(AB)=2010=10n(A' \cap B) = 20 - 10 = 10
step 5
To find n(AB)n(A \cap B'), we use the formula: n(AB)=n(A)n(AB)n(A \cap B') = n(A) - n(A \cap B). Substituting the values, we get n(AB)=3510=25n(A \cap B') = 35 - 10 = 25
Answer
n(AB)=45n(A \cup B) = 45, n(AB)=10n(A \cap B) = 10, n(AB)=10n(A' \cap B) = 10, n(AB)=25n(A \cap B') = 25
Key Concept
Set operations and their properties
Explanation
We used the properties of set operations and the given values to find the required quantities. The key formulas used were for the union and intersection of sets.
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