Solution by Steps
step 1
An experiment allows for control over variables, ensuring that the only difference between groups is the treatment (corked vs. noncorked bats)
step 2
Using available data may include confounding variables that could affect the outcome, making it difficult to determine causality
step 3
Randomization in an experiment helps to eliminate bias and ensures that the results are due to the treatment and not other factors
Answer
Investigating this question using an experiment is better because it allows for control over variables, eliminates confounding factors, and ensures that the results are due to the treatment.
Question b) What are the explanatory and response variables in this experiment?
step 1
The explanatory variable is the type of bat used (corked or noncorked)
step 2
The response variable is the distance the ball is hit
Answer
The explanatory variable is the type of bat used (corked or noncorked), and the response variable is the distance the ball is hit.
Question c) What are the treatments in the experiment?
step 1
The treatments in the experiment are the use of a corked bat and the use of a noncorked bat
Answer
The treatments are the use of a corked bat and the use of a noncorked bat.
Question d) Why is it important to randomize the order of the bats?
step 1
Randomizing the order of the bats helps to eliminate any potential order effects or biases that could influence the results
step 2
It ensures that the results are due to the treatment and not the order in which the bats are used
Answer
Randomizing the order of the bats is important to eliminate order effects and ensure that the results are due to the treatment.
Question e) Explain the concept of control and how it should be used in this experiment.
step 1
Control involves keeping all other variables constant except for the treatment being tested
step 2
In this experiment, control can be achieved by using the same player, same pitching conditions, and same environment for both types of bats
Answer
Control involves keeping all other variables constant except for the treatment. In this experiment, it can be achieved by using the same player, same pitching conditions, and same environment for both types of bats.
Question f) Will you be blind in this experiment? Explain how this could limit the conclusions we can make.
step 1
Blinding means that the participant does not know which treatment they are receiving
step 2
In this experiment, it may be difficult to blind the player to the type of bat being used
step 3
Lack of blinding could introduce bias, as the player's performance might be influenced by their knowledge of the bat type
Answer
Blinding means the participant does not know which treatment they are receiving. In this experiment, it may be difficult to blind the player, which could introduce bias and limit the conclusions we can make.
Question g) State the hypotheses we are interested in testing.
step 1
The null hypothesis (H0) is that there is no difference in the mean distance hit between corked and noncorked bats step 2
The alternative hypothesis (Ha) is that there is a difference in the mean distance hit between corked and noncorked bats Answer
The null hypothesis ($H_0$) is that there is no difference in the mean distance hit between corked and noncorked bats. The alternative hypothesis ($H_a$) is that there is a difference.
Question h) Describe a Type I and a Type II error in the context of these hypotheses.
step 1
A Type I error occurs when we reject the null hypothesis when it is actually true
step 2
In this context, a Type I error would mean concluding that corking the bat makes a difference when it actually does not
step 3
A Type II error occurs when we fail to reject the null hypothesis when it is actually false
step 4
In this context, a Type II error would mean concluding that corking the bat does not make a difference when it actually does
Answer
A Type I error would mean concluding that corking the bat makes a difference when it actually does not. A Type II error would mean concluding that corking the bat does not make a difference when it actually does.
Question i) Calculate the value of the test statistic (difference in means).
step 1
The mean distance for the corked bat is 225 feet
step 2
The mean distance for the noncorked bat is 221 feet
step 3
The test statistic is the difference in means: 225−221=4 feet Answer
The value of the test statistic (difference in means) is 4 feet.
Question j) Describe how to simulate the distribution of the difference in means, assuming you have the same ABILITY to hit with each type of bat.
step 1
Combine all the distances hit with both types of bats into one dataset
step 2
Randomly split this combined dataset into two groups of 20 distances each
step 3
Calculate the difference in means between the two groups
step 4
Repeat this process 100 times to create a distribution of the difference in means
Answer
To simulate the distribution of the difference in means, combine all distances into one dataset, randomly split into two groups of 20, calculate the difference in means, and repeat 100 times.
Question k) Describe what information is provided by the dotplot.
step 1
The dotplot shows the distribution of the simulated differences in means from 100 trials
step 2
It provides a visual representation of the variability and range of the differences in means
step 3
It helps to determine if the observed difference in means is unusual compared to the simulated differences
Answer
The dotplot shows the distribution of the simulated differences in means from 100 trials, providing a visual representation of variability and helping to determine if the observed difference is unusual.
Question l) Use the dotplot to estimate and interpret the p-value.
step 1
The p-value is the proportion of simulated differences that are as extreme or more extreme than the observed difference step 2
Count the number of dots in the dotplot that are as extreme or more extreme than the observed difference of 4 feet
step 3
Divide this count by the total number of trials (100) to estimate the p-value Answer
The $p$-value is estimated by counting the number of dots as extreme or more extreme than 4 feet and dividing by 100.
Question m) Based on this p-value, what would be an appropriate conclusion?
step 1
If the p-value is less than the significance level (e.g., 0.05), we reject the null hypothesis step 2
If the p-value is greater than the significance level, we fail to reject the null hypothesis Answer
Based on the $p$-value, if it is less than 0.05, we reject the null hypothesis and conclude that corking the bat makes a difference. If it is greater than 0.05, we fail to reject the null hypothesis.
Question n) If your conclusion was in error, which type of error did you make? Explain. What can you do to reduce the chances of making this type of error?
step 1
If we rejected the null hypothesis incorrectly, we made a Type I error
step 2
If we failed to reject the null hypothesis incorrectly, we made a Type II error
step 3
To reduce Type I error, we can lower the significance level
step 4
To reduce Type II error, we can increase the sample size
Answer
If we rejected the null hypothesis incorrectly, we made a Type I error. If we failed to reject it incorrectly, we made a Type II error. To reduce Type I error, lower the significance level; to reduce Type II error, increase the sample size.
Key Concept
Explanation
Hypothesis testing involves making decisions about population parameters based on sample data, with potential errors being Type I (false positive) and Type II (false negative).