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阅读图片做出这个题目要详细的过程画出来三视图 FHM, Wirtschaftsingenieur (BA-WI-xx-F-VZ), Maschinenel...

Aug 19, 2024

阅读图片做出这个题目要详细的过程画出来三视图

Solution

To create the three views (front, top, and side) of the hinge, we start by identifying the key dimensions from the technical drawing. The horizontal bore has a diameter of 7 mm, and the two vertical bores also have a diameter of 7 mm with a depth of 11 mm. The distance between the two vertical bores is 35 mm. We will represent these dimensions accurately in each view

In the front view, we will show the hinge as a U-shaped object with the two vertical bores visible. The horizontal bore will not be visible in this view. The dimensions will be labeled accordingly

In the top view, we will depict the hinge from above, showing the horizontal bore clearly and the two vertical bores as circles. The distance between the centers of the vertical bores will be marked as 35 mm

The side view will illustrate the depth of the vertical bores, showing the 11 mm depth clearly. The horizontal bore will also be represented in this view, indicating its diameter of 7 mm. All views will include appropriate dimension lines and labels for clarity

Answer

The three views of the hinge are accurately represented with all dimensions labeled.

Key Concept

Technical drawing and dimensioning are essential in engineering to convey the design and specifications of mechanical components. The three-view drawing method provides a comprehensive understanding of the object's geometry.

Explanation

By accurately representing the hinge in three views, we ensure that all dimensions are clear, allowing for proper manufacturing and assembly. This process is crucial in mechanical design.

根据Bild 5 6 7 8 做出Aufgabe 11

Solution

To determine the minimum diameter

d_{\text{min}}

required at the smallest cross-section of the crane hook, we first need to calculate the maximum load that the hook will experience. The maximum load is given as 100 t, and we must account for a safety reserve of 20%. Thus, the effective load

F

is calculated as:

F = 100 \, \text{t} \times (1 + 0.2) = 120 \, \text{t} = 120,000 \, \text{N}

Next, we will use the yield strength

R_{p,2}

of the material (34CrNiMo6) and the safety factor

S_g

against plastic deformation, which is 1.5 from Bild 7. The required minimum diameter can be calculated using the formula:

d_{\text{min}} = \sqrt{\frac{4F}{\pi R_{p,2}/S_g}}

Substituting the values will give us the minimum diameter

For the material 34CrNiMo6, we need to refer to Bild 6 for the yield strength

R_{p,2}

. Assuming

R_{p,2}

is approximately 800 MPa (minimum value), we can substitute this into our equation:

d_{\text{min}} = \sqrt{\frac{4 \times 120,000 \, \text{N}}{\pi \times (800 \times 10^6 \, \text{Pa}/1.5)}}

Calculating this will yield the minimum diameter required for the hook

For part b, we need to select an axial groove ball bearing from Bild 8. The bearing must have a dynamic load rating that meets or exceeds the calculated load from part a, considering the safety factor of 1.1. We will look for a bearing in the table that meets these criteria. The selection process involves checking the load ratings against the calculated load to ensure safety and functionality

Answer

[Insert final answer here]

Key Concept

Static Equilibrium: The forces acting on the crane hook must be balanced to ensure it does not fail under load. The safety factors and material properties are crucial in determining the dimensions required for safe operation.

Explanation

The calculations for the minimum diameter and bearing selection ensure that the crane hook can safely support the maximum load with the required safety margins. This is essential for the structural integrity and safety of the crane operation.