Solution
a
Calculate the density of the solid sphere (A) using its mass and volume
$$ \rho_A = \frac{m_A}{V_A} = \frac{128 \text{ g}}{16 \text{ cm}^3} = 8 \text{ g/cm}^3 $$
b
Calculate the density of the hollow sphere (B) using its mass and volume
$$ \rho_B = \frac{m_B}{V_B} = \frac{60 \text{ g}}{12 \text{ cm}^3} = 5 \text{ g/cm}^3 $$
c
Since A and B are made of the same material, their densities should be equal. Use the density of A to find the volume of the hollow part of B
$$ V_{\text{hollow}} = V_B - \frac{m_B}{\rho_A} = 12 \text{ cm}^3 - \frac{60 \text{ g}}{8 \text{ g/cm}^3} = 4.5 \text{ cm}^3 $$
d
Calculate the mass of a solid sphere A with a volume of 60 cm³ using the density of A
$$ m_{A_{60cm^3}} = \rho_A \times 60 \text{ cm}^3 = 8 \text{ g/cm}^3 \times 60 \text{ cm}^3 = 480 \text{ g} = 0.480 \text{ kg} $$
Answer
①空心球空心部分的体积是4.5立方厘米;②体积是60cm³的A金属球它的质量是0.480kg
Key Concept
Density and its relation to mass and volume: ρ=Vm Explanation
The density of a material is constant, so we can use the density of one object to find the mass or volume of another object made of the same material.