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50 E In Fig. 26.22, a battery of potential difference V=16 VV=16 \mathrm{~V} is con...
May 8, 2024
a Answer
The electron moves from the positive end to the negative end of the battery.
a Solution
b Answer
The work done on the electron by the electric field is 2.56×1018 2.56 \times 10^{-18} joules.
b Solution
c Answer
The energy transferred to the thermal energy of the strip is 2.56×1018 2.56 \times 10^{-18} joules.
c Solution
Key Concept
Direction of electron movement in an electric field
Explanation
Electrons move from lower to higher electric potential, which is from the positive to the negative terminal in a circuit.
Key Concept
Work done on a charge by an electric field
Explanation
The work done on a charge in an electric field is the product of the charge and the potential difference it moves through, given by W=qV W = qV .
Key Concept
Energy transfer to thermal energy
Explanation
The work done on the electron by the electric field is converted into thermal energy in the resistive strip.
A
Key Concept
Kirchhoff's loop rule and charging of capacitors
Explanation
At t=0t=0, the capacitor behaves like a short circuit, so the current i1i_1 is determined by the voltage of the battery divided by the resistance R1R_1.
B
Key Concept
Current division in parallel resistors at initial charging
Explanation
At t=0t=0, since the capacitor acts as a short circuit, i2i_2 is zero because all the current flows through the capacitor and R1R_1, not through R2R_2.
C
Key Concept
Current division in parallel resistors at initial charging
Explanation
At t=0t=0, i3i_3 is also zero for the same reason as i2i_2: all the current flows through the capacitor and R1R_1.
D
Key Concept
Steady-state current in a DC circuit with a fully charged capacitor
Explanation
At t=t=\infty, the capacitor is fully charged and acts as an open circuit, so i1i_1 is zero because no current flows through an open circuit.
E
Key Concept
Steady-state current in parallel resistors
Explanation
At t=t=\infty, i2i_2 is determined by the voltage of the battery divided by the resistance R2R_2 because the capacitor no longer allows current to flow through it.
F
Key Concept
Steady-state current in parallel resistors
Explanation
At t=t=\infty, i3i_3 is the same as i2i_2 because R2R_2 and R3R_3 are identical and in parallel, so they share the same voltage drop and carry the same current.
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