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2. Consider the following expected returns, volatilities, and correlations: \be...
May 7, 2024
Solution
a
To ensure a risk-free investment with stocks Vital and Mital, we need to find the weights of the portfolio that eliminate risk. Since Vital and Mital have a perfect negative correlation of -1.0, a risk-free portfolio can be created by allocating the investments in a way that the weighted returns of one stock offset the weighted returns of the other
b
Let ww be the weight of the investment in Vital and (1w)(1-w) be the weight of the investment in Mital. The portfolio's variance is given by the formula: Var(P)=w2σVital2+(1w)2σMital2+2w(1w)σVitalσMitalρVital,MitalVar(P) = w^2\sigma_{Vital}^2 + (1-w)^2\sigma_{Mital}^2 + 2w(1-w)\sigma_{Vital}\sigma_{Mital}\rho_{Vital,Mital}, where ρVital,Mital\rho_{Vital,Mital} is the correlation coefficient between Vital and Mital. Since ρVital,Mital=1\rho_{Vital,Mital} = -1, the cross-product term will cancel out the individual variances if the weights are chosen correctly
c
To find the weight ww, we set the portfolio's variance to zero and solve for ww: 0=w2σVital2+(1w)2σMital22w(1w)σVitalσMital0 = w^2\sigma_{Vital}^2 + (1-w)^2\sigma_{Mital}^2 - 2w(1-w)\sigma_{Vital}\sigma_{Mital}. Simplifying this equation will give us the weight ww that needs to be invested in Vital to ensure a risk-free investment
d
Solving the equation from step c, we get: w=σMitalσVital+σMitalw = \frac{\sigma_{Mital}}{\sigma_{Vital} + \sigma_{Mital}}. Plugging in the values σVital=6%\sigma_{Vital} = 6\% and σMital=24%\sigma_{Mital} = 24\%, we find w=246+24=2430=0.8w = \frac{24}{6 + 24} = \frac{24}{30} = 0.8
Answer
The portion of the investment that should be allocated to Vital stock to ensure a risk-free investment is 80%.
Key Concept
Portfolio variance and correlation
Explanation
By understanding the relationship between the variances of individual stocks and their correlation, we can determine the weights of a portfolio that minimize risk, in this case, creating a risk-free portfolio due to perfect negative correlation.
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