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某兴趣小组准备将一棱长为 aa 的正方体木块打磨成圆锥,则圆锥的最大体积为
Mar 8, 2024
某兴趣小组准备将一棱长为 aa 的正方体木块打磨成圆锥,则圆锥的最大体积为
Solution by Steps
step 1
Consider a cone inscribed in a cube with side length aa. The cone's height hh and base radius rr will be related to the cube's side length
step 2
The volume VV of a cone is given by the formula V=13πr2hV = \frac{1}{3}\pi r^2 h
step 3
To maximize the volume, we need to express VV in terms of a single variable. Since the cone is inscribed in the cube, the height hh plus twice the radius 2r2r equals the side length aa of the cube, so h=a2rh = a - 2r
step 4
Substitute hh into the volume formula to get V=13πr2(a2r)V = \frac{1}{3}\pi r^2 (a - 2r)
step 5
To find the maximum volume, take the derivative of VV with respect to rr and set it equal to zero: dVdr=13π(2ra6r2)\frac{dV}{dr} = \frac{1}{3}\pi (2ra - 6r^2)
step 6
Solve dVdr=0\frac{dV}{dr} = 0 for rr to find the critical points
step 7
The critical point that maximizes the volume occurs when r=a3r = \frac{a}{3}
step 8
Substitute r=a3r = \frac{a}{3} back into the expression for hh to find h=a2(a3)=a3h = a - 2(\frac{a}{3}) = \frac{a}{3}
step 9
Now substitute r=a3r = \frac{a}{3} and h=a3h = \frac{a}{3} into the volume formula to find the maximum volume: Vmax=13π(a3)2(a3)V_{max} = \frac{1}{3}\pi (\frac{a}{3})^2 (\frac{a}{3})
step 10
Simplify the expression for VmaxV_{max} to get Vmax=13πa327=πa381V_{max} = \frac{1}{3}\pi \frac{a^3}{27} = \frac{\pi a^3}{81}
Answer
Vmax=πa381V_{max} = \frac{\pi a^3}{81}
Key Concept
Maximizing the volume of a cone inscribed in a cube
Explanation
The maximum volume of a cone inscribed in a cube is found by expressing the volume in terms of one variable, taking the derivative, finding the critical points, and then substituting back to find the maximum volume.
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