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已知集合 $M \subseteq\left\{x \mid x=i^{n}+\mathrm{i}^{-n}, n \in \mathrm{N}_{+}\rig...
Mar 8, 2024
已知集合 M{xx=in+in,nN+}M \subseteq\left\{x \mid x=i^{n}+\mathrm{i}^{-n}, n \in \mathrm{N}_{+}\right\}(其中 i\mathrm{i} 为虚数单位),则满足条件的集合 MM 的个数为
Solution by Steps
step 1
Identify the pattern of the powers of the imaginary unit i
step 2
Recall that i2=1 i^2 = -1 , i3=i i^3 = -i , i4=1 i^4 = 1 , and the powers of i repeat every four terms
step 3
Calculate the expression in+in i^n + i^{-n} for the first few positive integers to find a pattern
step 4
Observe that in+in i^n + i^{-n} will always be real because the imaginary parts cancel out
step 5
Note that for n=4k n = 4k and n=4k+2 n = 4k+2 (where k is a non-negative integer), the expression in+in i^n + i^{-n} equals 2 or -2, respectively
step 6
For n=4k+1 n = 4k+1 and n=4k+3 n = 4k+3 , the expression in+in i^n + i^{-n} equals 0
step 7
Determine the possible values for x in the set M
step 8
Since the possible values for x are 2, -2, and 0, the subsets of M can include any combination of these values
step 9
Count the number of subsets of M, including the empty set
step 10
There are 2^3 = 8 possible subsets of M, including the empty set
Answer
8
Key Concept
Powers of the imaginary unit and subset counting
Explanation
The powers of i repeat every four terms, and the sum in+in i^n + i^{-n} will only yield the values 2, -2, or 0. The number of subsets of a set with three distinct elements is 23 2^3 , including the empty set.
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