已知曲线 C1、C2 分别是函数 y=-\frac{4}{x}(x<0), y=\frac{k}{x}(k>0, x>0) 的图像, 边长为 6 的正 △ABC 的顶点 A 在 y 轴正半轴上, 顶点 B、C 在 x轴上 ( B 在 C 的左侧) , 现将 △ABC 绕原点 O 函时针筂转, 当点 B 在曲线 C1 上时, 点 A 恰好在曲线 C2 上, 则k的值为
Solution by Steps
step 1
Identify the coordinates of vertices A, B, and C
step 2
Since vertex A is on the positive y-axis and the triangle is equilateral with side length 6, the coordinates of A are (0, 6)
step 3
Vertices B and C are on the x-axis, so their y-coordinates are 0. The x-coordinate of B is negative, and C is positive
step 4
The distance between B and C is the side length of the triangle, which is 6. So, if B is at (-3, 0), then C is at (3, 0)
step 5
When the triangle is rotated, vertex B will lie on curve C1 and vertex A will lie on curve C2
step 6
The equation of curve C1 is y=−x4 for x < 0
step 7
The equation of curve C2 is y=xk for k > 0 and x > 0
step 8
Since B lies on C1, we substitute the coordinates of B into the equation of C1 to find the value of y when x is -3
step 9
Substituting B into C1 gives y=−−34=34
step 10
Since A lies on C2, we substitute the coordinates of A into the equation of C2 to find the value of k when x is 3
step 11
Substituting A into C2 gives 6=3k, which implies k=18
Answer
k = 18
Key Concept
Finding the value of k for a rotated equilateral triangle with vertices on given curves
Explanation
By placing the vertices of the equilateral triangle on the given curves and using the side length, we can solve for the unknown value k in the equation of curve C2.