Logo

AskSia

Plus

实数 x,yx, y 满足 x2+2xy3y2=1x^{2}+2 x y-3 y^{2}=1 ,则 x2+y2x^{2}+y^{2} 的最小值是
Mar 8, 2024
实数 x,yx, y 满足 x2+2xy3y2=1x^{2}+2 x y-3 y^{2}=1 ,则 x2+y2x^{2}+y^{2} 的最小值是
Generated Graph
Solution by Steps
step 1
To find the minimum value of x2+y2 x^2 + y^2 subject to the constraint x2+2xy3y2=1 x^2 + 2xy - 3y^2 = 1 , we can use the method of Lagrange multipliers or directly find the critical points of the function
step 2
The asksia-ll calculator has computed the minimum value of x2+y2 x^2 + y^2 given the constraint and found two points where this minimum occurs: (0.875392,0.206652)(-0.875392, -0.206652) and (0.875392,0.206652)(0.875392, 0.206652)
step 3
The minimum value of x2+y2 x^2 + y^2 subject to the given constraint is approximately 0.809017 0.809017
Answer
The minimum value of x2+y2 x^2 + y^2 subject to the constraint x2+2xy3y2=1 x^2 + 2xy - 3y^2 = 1 is approximately 0.809017 0.809017 .
Key Concept
Optimization with constraints
Explanation
The minimum value of a function subject to a constraint can be found using optimization techniques such as Lagrange multipliers, which is likely the method used by the asksia-ll calculator to find the approximate minimum value.
© 2023 AskSia.AI all rights reserved