Define the function f(x) for x∈(0,1] as given: f(x)=4x(x−1)
step 2
Find the value of f(x) at the endpoints of the interval (0,1]: f(0) and f(1)
step 3
Calculate f(0) using the definition of f(x): f(0)=4⋅0⋅(0−1)=0
step 4
Calculate f(1) using the definition of f(x): f(1)=4⋅1⋅(1−1)=0
step 5
Determine the critical points of f(x) in the interval (0,1] by setting the derivative f′(x) equal to zero and solving for x
step 6
Compute the derivative: f′(x)=4(2x−1)
step 7
Set the derivative equal to zero: 4(2x−1)=0
step 8
Solve for x: x=21
step 9
Evaluate f(x) at x=21: f(21)=4⋅21⋅(21−1)=−1
step 10
Since f(x)≥−3 for x∈(0,1], and the minimum value of f(x) in this interval is −1, the condition is satisfied for x∈(0,1]
step 11
Use the functional equation f(x+1)=2f(x) to extend the definition of f(x) to x∈(−∞,0]
step 12
Find the largest value of m such that f(x)≥−3 for all x∈(−∞,m]
step 13
Since f(x) is defined recursively, check values of f(x) for x∈(−∞,0] using the functional equation
step 14
For x=0, f(x)=0≥−3. For x=−1, f(−1)=2f(0)=0≥−3. Continue checking values of x until f(x) < -3
step 15
Since f(x) is decreasing for x < 0, find the first x such that f(x) < -3
step 16
The value of m is the largest x for which f(x)≥−3
Answer
The value of m is the largest x for which f(x)≥−3.
Key Concept
Recursive Function and Interval Analysis
Explanation
The key concept involves understanding the recursive nature of the function f(x) and analyzing its behavior over different intervals to find the maximum value of m such that f(x)≥−3 for all x∈(−∞,m].