Logo

AskSia

Plus

函数 f(x)f(x) 的定义域为 R\mathrm{R}, 满足 f(x+1)=2f(x)f(x+1)=2 f(x) ,且当 x(0,1]x \in(0,1] 时, $f(x)=4 x(x...
Mar 8, 2024
函数 f(x)f(x) 的定义域为 R\mathrm{R}, 满足 f(x+1)=2f(x)f(x+1)=2 f(x) ,且当 x(0,1]x \in(0,1] 时, f(x)=4x(x1)f(x)=4 x(x-1) ,若对任意的 x(,m]x \in(-\infty, m] ,都有 f(x)3f(x) \geq-3 ,则 mm 的取值范围是
Solution by Steps
step 1
Define the function f(x)f(x) for x(0,1]x \in (0,1] as given: f(x)=4x(x1)f(x) = 4x(x-1)
step 2
Find the value of f(x)f(x) at the endpoints of the interval (0,1](0,1]: f(0)f(0) and f(1)f(1)
step 3
Calculate f(0)f(0) using the definition of f(x)f(x): f(0)=40(01)=0f(0) = 4 \cdot 0 \cdot (0-1) = 0
step 4
Calculate f(1)f(1) using the definition of f(x)f(x): f(1)=41(11)=0f(1) = 4 \cdot 1 \cdot (1-1) = 0
step 5
Determine the critical points of f(x)f(x) in the interval (0,1](0,1] by setting the derivative f(x)f'(x) equal to zero and solving for xx
step 6
Compute the derivative: f(x)=4(2x1)f'(x) = 4(2x-1)
step 7
Set the derivative equal to zero: 4(2x1)=04(2x-1) = 0
step 8
Solve for xx: x=12x = \frac{1}{2}
step 9
Evaluate f(x)f(x) at x=12x = \frac{1}{2}: f(12)=412(121)=1f\left(\frac{1}{2}\right) = 4 \cdot \frac{1}{2} \cdot \left(\frac{1}{2}-1\right) = -1
step 10
Since f(x)3f(x) \geq -3 for x(0,1]x \in (0,1], and the minimum value of f(x)f(x) in this interval is 1-1, the condition is satisfied for x(0,1]x \in (0,1]
step 11
Use the functional equation f(x+1)=2f(x)f(x+1) = 2f(x) to extend the definition of f(x)f(x) to x(,0]x \in (-\infty, 0]
step 12
Find the largest value of mm such that f(x)3f(x) \geq -3 for all x(,m]x \in (-\infty, m]
step 13
Since f(x)f(x) is defined recursively, check values of f(x)f(x) for x(,0]x \in (-\infty, 0] using the functional equation
step 14
For x=0x = 0, f(x)=03f(x) = 0 \geq -3. For x=1x = -1, f(1)=f(0)2=03f(-1) = \frac{f(0)}{2} = 0 \geq -3. Continue checking values of xx until f(x) < -3
step 15
Since f(x)f(x) is decreasing for x < 0, find the first xx such that f(x) < -3
step 16
The value of mm is the largest xx for which f(x)3f(x) \geq -3
Answer
The value of mm is the largest xx for which f(x)3f(x) \geq -3.
Key Concept
Recursive Function and Interval Analysis
Explanation
The key concept involves understanding the recursive nature of the function f(x)f(x) and analyzing its behavior over different intervals to find the maximum value of mm such that f(x)3f(x) \geq -3 for all x(,m]x \in (-\infty, m].
© 2023 AskSia.AI all rights reserved