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Задача 21. Среднее время сборки изделия составляло 90 минут. Инженер изобрел но...
Jun 21, 2024
Solution by Steps
step 1
First, we need to calculate the sample mean
x
ˉ
\bar{x}
x
ˉ
of the given data:
79
,
74
,
112
,
95
,
83
,
96
,
77
,
84
,
70
,
90
79, 74, 112, 95, 83, 96, 77, 84, 70, 90
79
,
74
,
112
,
95
,
83
,
96
,
77
,
84
,
70
,
90
step 2
The sample mean
x
ˉ
\bar{x}
x
ˉ
is calculated as follows:
x
ˉ
=
79
+
74
+
112
+
95
+
83
+
96
+
77
+
84
+
70
+
90
10
=
860
10
=
86
\bar{x} = \frac{79 + 74 + 112 + 95 + 83 + 96 + 77 + 84 + 70 + 90}{10} = \frac{860}{10} = 86
x
ˉ
=
10
79
+
74
+
112
+
95
+
83
+
96
+
77
+
84
+
70
+
90
=
10
860
=
86
minutes
step 3
Next, we calculate the sample standard deviation
s
s
s
. The formula for the sample standard deviation is
s
=
∑
(
x
i
−
x
ˉ
)
2
n
−
1
s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}
s
=
n
−
1
∑
(
x
i
−
x
ˉ
)
2
step 4
Calculate each
(
x
i
−
x
ˉ
)
2
(x_i - \bar{x})^2
(
x
i
−
x
ˉ
)
2
:
(
79
−
86
)
2
=
49
(79-86)^2 = 49
(
79
−
86
)
2
=
49
,
(
74
−
86
)
2
=
144
(74-86)^2 = 144
(
74
−
86
)
2
=
144
,
(
112
−
86
)
2
=
676
(112-86)^2 = 676
(
112
−
86
)
2
=
676
,
(
95
−
86
)
2
=
81
(95-86)^2 = 81
(
95
−
86
)
2
=
81
,
(
83
−
86
)
2
=
9
(83-86)^2 = 9
(
83
−
86
)
2
=
9
,
(
96
−
86
)
2
=
100
(96-86)^2 = 100
(
96
−
86
)
2
=
100
,
(
77
−
86
)
2
=
81
(77-86)^2 = 81
(
77
−
86
)
2
=
81
,
(
84
−
86
)
2
=
4
(84-86)^2 = 4
(
84
−
86
)
2
=
4
,
(
70
−
86
)
2
=
256
(70-86)^2 = 256
(
70
−
86
)
2
=
256
,
(
90
−
86
)
2
=
16
(90-86)^2 = 16
(
90
−
86
)
2
=
16
step 5
Sum these values:
49
+
144
+
676
+
81
+
9
+
100
+
81
+
4
+
256
+
16
=
1416
49 + 144 + 676 + 81 + 9 + 100 + 81 + 4 + 256 + 16 = 1416
49
+
144
+
676
+
81
+
9
+
100
+
81
+
4
+
256
+
16
=
1416
step 6
Calculate the sample variance:
1416
10
−
1
=
1416
9
=
157.33
\frac{1416}{10-1} = \frac{1416}{9} = 157.33
10
−
1
1416
=
9
1416
=
157.33
step 7
The sample standard deviation
s
s
s
is
157.33
≈
12.54
\sqrt{157.33} \approx 12.54
157.33
≈
12.54
minutes
step 8
To construct a 95% confidence interval for the mean, we use the formula
x
ˉ
±
t
α
/
2
s
n
\bar{x} \pm t_{\alpha/2} \frac{s}{\sqrt{n}}
x
ˉ
±
t
α
/2
n
s
step 9
For a 95% confidence level and
n
−
1
=
9
n-1 = 9
n
−
1
=
9
degrees of freedom, the critical value
t
α
/
2
t_{\alpha/2}
t
α
/2
from the t-distribution table is approximately 2.262
step 10
Calculate the margin of error:
E
=
t
α
/
2
s
n
=
2.262
12.54
10
≈
8.98
E = t_{\alpha/2} \frac{s}{\sqrt{n}} = 2.262 \frac{12.54}{\sqrt{10}} \approx 8.98
E
=
t
α
/2
n
s
=
2.262
10
12.54
≈
8.98
step 11
The confidence interval is:
86
±
8.98
86 \pm 8.98
86
±
8.98
, which gives us
(
77.02
,
94.98
)
(77.02, 94.98)
(
77.02
,
94.98
)
Answer
The 95% confidence interval for the new mean assembly time is
(
77.02
,
94.98
)
(77.02, 94.98)
(
77.02
,
94.98
)
minutes.
Key Concept
Confidence Interval
Explanation
A confidence interval provides a range of values that is likely to contain the population mean with a certain level of confidence, in this case, 95%.
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