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solve each question step by step with detail Check that you have all FOUR pages ...
Mar 27, 2024
solve each question step by step with detail Check that you have all FOUR pages of the assignment. Answer all questions in the spaces provided. Scientific calculators (non-graphing, non-programmable) are permitted but may not be shared. A Communication mark out of 3 will be assigned throughout the assignment. “Look-Fors”: proper mathematical notation and terminology used, therefore statements, formulas, neat diagrams, complete and clear solutions, showing ALL steps. KNOWLEDGE/UNDERSTANDING [10 marks] 1. When a polynomial p(x) is divided by x+3 the quotient is x 2 − 4x + 5 with a remainder of 7. [3 marks total] a) Express this division in quotient form. [1 mark] b) What is the polynomial, p(x), in standard form? [2 marks] 2. When P(x) = (kx 3 + 3x 2 − 12x − 3) is divided by x+1, the remainder is 4. Determine the value of k. [3 marks] 3. Solve (−3x)(x + 7)(x − 2) ≥ 0 , using an interval chart. Express your answer in proper set notation. [4 marks] Zeroes factors Answer: ______________________________________________________________________ K A T C / 10 / 12 / 8 / 5 APPLICATION [12 marks] 1. The population of a town, t years from now, is modelled by P(t)= t3 -7t2 +7t +115 where P(t) is measured in thousands of people. When is the population of this town greater than 100 thousand people? Be sure to include a therefore statement and interpret your results in the context of this question. [6 marks] 2. A piece of cardboard measuring 40cm by 30cm is used to create an open-top box. [6 marks total] a) Express the volume of the box as a function of x, in factored form. [1 mark] b) What are the possible dimensions (to one decimal place) of the square corners that will need to be removed to create a box of volume 2448cm3 ? [5 marks] THINKING/INQUIRY [8 marks] 1. When the polynomial 4 3 2 6 3 4 x ax bx x     is divided by x 1 the remainder is 10. When it’s divided by x 2 the remainder is 106. Determine the values of a and b. Provide an algebraic solution, showing all work. [4 marks] 2. Sketch a graph of a quartic polynomial function y = f(x) such that: [4 marks]  f(x) > 0 when −2 < x < −1  f(x) < 0 when x < −2, −1 < x < 1, and x > 1 COMMUNICATION [5 marks] 1. Explain two distinct methods to find the remainder when dividing a polynomial, P(x), by a binomial (ax-b). [2 marks] OVERALL Comm / [3 marks] “Look-Fors”: proper mathematical notation and terminology used, therefore statements, formulas, neat diagrams, complete and clear solutions, showing ALL steps. Useful factoring formulas: x 2 + 2xy + y 2 = (x + y) 2 x 2 − 2xy + y 2 = (x − y) 2 x 2 − y 2 = (x + y)(x − y) x 3 + y 3 = (x + y)(x 2 − xy + y 2 ) x 3 − y 3 = (x − y)(x 2 + xy + y 2 ) Quadratic formula: x = −b ± √b 2 − 4ac 2a (Page intentionally left blank) Scrap notes on this page will not be graded, but you must submit it with your test.
Generated Graph
Solution by Steps
step 1
To express the division of the polynomial p(x) p(x) by x+3 x+3 in quotient form, we use the given quotient and remainder
step 2
The quotient form is p(x)=(x+3)(x24x+5)+7 p(x) = (x+3)(x^2 - 4x + 5) + 7
step 3
To find the polynomial p(x) p(x) in standard form, we expand the product and add the remainder
step 4
Expanding the product: (x+3)(x24x+5)=x34x2+5x+3x212x+15 (x+3)(x^2 - 4x + 5) = x^3 - 4x^2 + 5x + 3x^2 - 12x + 15
step 5
Combining like terms: x3x27x+15 x^3 - x^2 - 7x + 15
step 6
Adding the remainder: p(x)=x3x27x+15+7 p(x) = x^3 - x^2 - 7x + 15 + 7
step 7
The polynomial in standard form is p(x)=x3x27x+22 p(x) = x^3 - x^2 - 7x + 22
Answer
p(x)=x3x27x+22 p(x) = x^3 - x^2 - 7x + 22
Key Concept
Expressing polynomial division in quotient form
Explanation
The quotient form of a polynomial division includes the divisor, the quotient, and the remainder. The polynomial p(x) p(x) is reconstructed by multiplying the divisor by the quotient and adding the remainder.
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Solution by Steps
step 1
Given the polynomial P(x)=kx3+3x212x3 P(x) = kx^3 + 3x^2 - 12x - 3 and the remainder when divided by x+1 x+1 is 4, we use the remainder theorem
step 2
According to the remainder theorem, P(1)=4 P(-1) = 4
step 3
Substitute x=1 x = -1 into P(x) P(x) : P(1)=k(1)3+3(1)212(1)3 P(-1) = k(-1)^3 + 3(-1)^2 - 12(-1) - 3
step 4
Simplify the expression: k+3+123=4 -k + 3 + 12 - 3 = 4
step 5
Solve for k k : k+12=4 -k + 12 = 4
step 6
Subtract 12 from both sides: k=8 -k = -8
step 7
Divide by -1: k=8 k = 8
Answer
k=8 k = 8
Key Concept
Using the Remainder Theorem
Explanation
The Remainder Theorem states that the remainder of the division of a polynomial by a linear binomial xa x - a is equal to P(a) P(a) . By substituting a=1 a = -1 into P(x) P(x) , we can solve for the unknown coefficient k k .
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Solution by Steps
step 1
To solve the inequality (3x)(x+7)(x2)0 (-3x)(x + 7)(x - 2) \geq 0 , we find the zeroes of the function
step 2
The zeroes are x=0 x = 0 , x=7 x = -7 , and x=2 x = 2
step 3
We create an interval chart to test the sign of the expression in each interval determined by the zeroes
step 4
The intervals are (,7) (-\infty, -7) , (7,0) (-7, 0) , (0,2) (0, 2) , and (2,) (2, \infty)
step 5
Test each interval to determine where the expression is non-negative
step 6
The solution set is x7 x \leq -7 or 0x2 0 \leq x \leq 2
Answer
{xRx7 or 0x2} \{ x \in \mathbb{R} | x \leq -7 \text{ or } 0 \leq x \leq 2 \}
Key Concept
Solving inequalities using an interval chart
Explanation
An interval chart helps to determine the sign of an expression within different intervals. By testing values in each interval, we can find where the expression is greater than or equal to zero.
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Solution by Steps
step 1
To determine when the population P(t) P(t) is greater than 100 thousand, we solve the inequality P(t) > 100
step 2
Substitute P(t) P(t) with the given expression: t^3 - 7t^2 + 7t + 115 > 100
step 3
Subtract 100 from both sides: t^3 - 7t^2 + 7t + 15 > 0
step 4
Find the values of t t for which the inequality holds true
step 5
Interpret the results in the context of the population growth
Answer
[The solution would be provided here based on the asksia-ll calculator result, which is not included in the provided context.]
Key Concept
Solving inequalities in context
Explanation
To find when the population exceeds a certain number, we solve the inequality representing the population model and interpret the solution in the context of time.
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Solution by Steps
step 1
To express the volume of the box as a function of x x , we use the dimensions of the cardboard and the size of the square corners cut out
step 2
The volume function V(x) V(x) is V(x)=x(402x)(302x) V(x) = x(40 - 2x)(30 - 2x)
step 3
To find the possible dimensions of the square corners for a volume of 2448cm3 2448 \text{cm}^3 , we solve V(x)=2448 V(x) = 2448
step 4
Factor the volume function and solve for x x
step 5
Interpret the results to determine the possible dimensions of the square corners
Answer
[The solution would be provided here based on the asksia-ll calculator result, which is not included in the provided context.]
Key Concept
Volume as a function of cut-out size
Explanation
The volume of an open-top box can be expressed as a function of the size of the square corners cut out from a piece of cardboard. By solving the volume function for a given volume, we can find the possible dimensions of the square corners.
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Solution by Steps
step 1
To determine the values of a a and b b in the polynomial 4x3+ax2+bx+6 4x^3 + ax^2 + bx + 6 , we use the given remainders from division by x1 x-1 and x+2 x+2
step 2
The remainder when divided by x1 x-1 is 10, and by x+2 x+2 is 106
step 3
Apply the Remainder Theorem: P(1)=10 P(1) = 10 and P(2)=106 P(-2) = 106
step 4
Substitute x=1 x = 1 into P(x) P(x) : 4(1)3+a(1)2+b(1)+6=10 4(1)^3 + a(1)^2 + b(1) + 6 = 10
step 5
Simplify and solve for a a and b b : 4+a+b+6=10 4 + a + b + 6 = 10
step 6
Substitute x=2 x = -2 into P(x) P(x) : 4(2)3+a(2)2+b(2)+6=106 4(-2)^3 + a(-2)^2 + b(-2) + 6 = 106
step 7
Simplify and solve for a a and b b : 32+4a2b+6=106 -32 + 4a - 2b + 6 = 106
step 8
Solve the system of equations to find a a and b b
Answer
[The solution would be provided here based on the asksia-ll calculator result, which is not included in the provided context.]
Key Concept
Using the Remainder Theorem to find polynomial coefficients
Explanation
The Remainder Theorem can be used to find unknown coefficients in a polynomial by setting up a system of equations based on the remainders from division by different binomials.
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Solution by Steps
step 1
To find the remainder when dividing a polynomial P(x) P(x) by a binomial axb ax-b , we can use long division or synthetic division
step 2
Long division involves dividing each term of the polynomial by the binomial and subtracting the result from the polynomial
step 3
Synthetic division is a shortcut method where we only use the coefficients of the polynomial and the zero of the binomial x=ba x = \frac{b}{a}
Answer
Two methods to find the remainder are long division and synthetic division.
Key Concept
Finding the remainder in polynomial division
Explanation
Long division is a step-by-step process that works for any polynomial division, while synthetic division is a quicker method that works when dividing by a binomial of the form xc x - c .
When a certain polynomial is divided by � − 2, the quotient is �2 + 4� − 7 and the remainder is −4. What is the polynomial?
Generated Graph
Solution by Steps
step 1
Given the quotient and remainder from the division of a polynomial by x2 x - 2 , we can express the original polynomial as the product of the divisor and the quotient, plus the remainder
step 2
The quotient is x2+6x+5 x^2 + 6x + 5 and the remainder is 6 6 . The divisor is x2 x - 2
step 3
Multiply the divisor x2 x - 2 by the quotient x2+6x+5 x^2 + 6x + 5 to get the main part of the polynomial
step 4
(x2)(x2+6x+5)=x3+4x27x10 (x - 2)(x^2 + 6x + 5) = x^3 + 4x^2 - 7x - 10
step 5
Add the remainder 6 6 to the result from step 4 to find the original polynomial
step 6
x3+4x27x10+6=x3+4x27x4 x^3 + 4x^2 - 7x - 10 + 6 = x^3 + 4x^2 - 7x - 4
Answer
The polynomial is x3+4x27x4 x^3 + 4x^2 - 7x - 4 .
Key Concept
Polynomial Long Division
Explanation
The original polynomial can be reconstructed by multiplying the divisor by the quotient and then adding the remainder.
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