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Apr 8, 2024
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Solution by Steps
step 1
To differentiate the function Y2x \frac{Y^2}{x} with respect to x x , we apply the quotient rule
step 2
The quotient rule states that (fg)=fgfgg2 \left(\frac{f}{g}\right)' = \frac{f'g - fg'}{g^2} , where f=Y2 f = Y^2 and g=x g = x . Since Y Y is treated as a constant with respect to x x , f=0 f' = 0
step 3
Applying the quotient rule, we get ddx(Y2x)=0xY21x2 \frac{d}{dx}\left(\frac{Y^2}{x}\right) = \frac{0 \cdot x - Y^2 \cdot 1}{x^2}
step 4
Simplifying the expression, we obtain Y2x2 -\frac{Y^2}{x^2} , assuming x0 x \neq 0
Answer
Y2x2 -\frac{Y^2}{x^2}
Key Concept
Differentiation using the quotient rule
Explanation
The quotient rule is used to differentiate ratios of functions, and in this case, it simplifies to Y2x2 -\frac{Y^2}{x^2} because the derivative of Y2 Y^2 with respect to x x is zero.
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