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draw a circle x^2+y^2=25
Feb 29, 2024
draw a circle x^2+y^2=25
Solution by Steps
step 1
To draw a circle with the equation x2+y2=25 x^2 + y^2 = 25 , we recognize that this is the standard form of a circle's equation centered at the origin (0,0)
step 2
The radius r r of the circle is the square root of 25, which is 5
step 3
Using a compass or a drawing tool, set the radius to 5 units. Place the point of the compass at the origin (0,0) and draw a full circle
Answer
The circle with the equation x2+y2=25 x^2 + y^2 = 25 has been drawn with a radius of 5 units centered at the origin.
Key Concept
Circle Equation in Standard Form
Explanation
The equation x2+y2=r2 x^2 + y^2 = r^2 represents a circle centered at the origin with radius r r . In this case, r=5 r = 5 .
draw y=3x+3
Solution by Steps
step 1
To draw the line y=3x+3 y = 3x + 3 , we need to find at least two points that satisfy the equation
step 2
Let's find the y-intercept by setting x=0 x = 0 . Plugging x=0 x = 0 into the equation gives us y=3(0)+3=3 y = 3(0) + 3 = 3 . So, one point is (0, 3)
step 3
Now, let's find the x-intercept by setting y=0 y = 0 . Solving 0=3x+3 0 = 3x + 3 for x x gives us x=−1 x = -1 . So, another point is (-1, 0)
step 4
With these two points, we can draw a straight line that passes through (0, 3) and (-1, 0)
Answer
The line y=3x+3 y = 3x + 3 has been drawn through the points (0, 3) and (-1, 0).
Key Concept
Drawing a Straight Line
Explanation
To draw a straight line given by the equation y=mx+b y = mx + b , we need at least two points. The y-intercept is found when x=0 x = 0 , and the x-intercept is found when y=0 y = 0 . Connecting these points gives us the line.
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