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6=4+mk−3=−814=p−1016−x=15\begin{array}{l}6=4+m \\ k-3=-8 \\ 14=p-10 \\ 16-x=15\end{array}
Feb 11, 2024
6=4+mk−3=−814=p−1016−x=15\begin{array}{l}6=4+m \\ k-3=-8 \\ 14=p-10 \\ 16-x=15\end{array}
Generated Graph
Solution by Steps
step 1
To solve for m m in the equation 6=4+m 6 = 4 + m , subtract 4 4 from both sides of the equation
step 2
Subtracting 4 4 from both sides gives us 6−4=m 6 - 4 = m
step 3
Simplifying 6−4 6 - 4 gives us m=2 m = 2
Answer
m=2 m = 2
Key Concept
Solving a linear equation by isolating the variable
Explanation
To find the value of m m , we isolate m m by performing the same operation on both sides of the equation.
Solution by Steps
step 1
To solve for k k in the equation k−3=−8 k - 3 = -8 , add 3 3 to both sides of the equation
step 2
Adding 3 3 to both sides gives us k−3+3=−8+3 k - 3 + 3 = -8 + 3
step 3
Simplifying gives us k=−5 k = -5
Answer
k=−5 k = -5
Key Concept
Solving a linear equation by isolating the variable
Explanation
To find the value of k k , we isolate k k by performing the same operation on both sides of the equation.
Solution by Steps
step 1
To solve for p p in the equation 14=p−10 14 = p - 10 , add 10 10 to both sides of the equation
step 2
Adding 10 10 to both sides gives us 14+10=p 14 + 10 = p
step 3
Simplifying 14+10 14 + 10 gives us p=24 p = 24
Answer
p=24 p = 24
Key Concept
Solving a linear equation by isolating the variable
Explanation
To find the value of p p , we isolate p p by performing the same operation on both sides of the equation.
Solution by Steps
step 1
To solve for x x in the equation 16−x=15 16 - x = 15 , subtract 16 16 from both sides of the equation
step 2
Subtracting 16 16 from both sides gives us −x=15−16 -x = 15 - 16
step 3
Simplifying 15−16 15 - 16 gives us −x=−1 -x = -1
step 4
Multiplying both sides by −1 -1 to solve for x x gives us x=1 x = 1
Answer
x=1 x = 1
Key Concept
Solving a linear equation by isolating the variable
Explanation
To find the value of x x , we isolate x x by performing the same operation on both sides of the equation and then multiplying by −1 -1 to get the positive value of x x .
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