The thirteenth term of an arithmetic progression is 12 and the sum of the first ...
Apr 11, 2024
The thirteenth term of an arithmetic progression is 12 and the sum of the first 30 terms is -15 . Find the sum of the first 50 terms of the progression. [5]
Solution by Steps
step 1
Let's denote the first term of the arithmetic progression as a1 and the common difference as d. The nth term of an arithmetic progression is given by an=a1+(n−1)d
step 2
Given that the 13th term a13 is 12, we can write the equation a13=a1+12d=12
step 3
The sum of the first n terms of an arithmetic progression is given by Sn=2n(2a1+(n−1)d)
step 4
Given that the sum of the first 30 terms S30 is -15, we can write the equation S30=230(2a1+29d)=−15
step 5
We now have a system of two equations: a1+12d=12 and 15(2a1+29d)=−15. We can solve this system to find a1 and d
step 6
Solving the system, we find the values of a1 and d
step 7
Once we have a1 and d, we can find the sum of the first 50 terms S50 using the formula from step 3 with n=50
step 8
Calculate S50=250(2a1+49d) using the found values of a1 and d
Answer
[Insert final answer here]
Key Concept
Arithmetic Progression Formulas
Explanation
To find the sum of the first 50 terms, we use the formulas for the nth term and the sum of the first n terms of an arithmetic progression. We first determine the first term and the common difference by solving a system of equations derived from the given information.
What is the formula to find the sum of the first n terms of an arithmetic progression?