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The sine of an angle is given by the table below: \begin{tabular}{|l|l|l|l|l|l|...
May 8, 2024
Generated Graph
Solution by Steps
step 2
On the horizontal axis, each 1 cm represents 1010^\circ. On the vertical axis, each 1 cm represents 0.1 units of sin(x)sin(x)
step 3
Plot the points from the table on the graph using the given scale
step 4
Draw a smooth curve through the plotted points to represent the sine function from 00^\circ to 9090^\circ
step 5
To find sin(55)sin(55^\circ), locate 5555^\circ on the horizontal axis and find the corresponding point on the curve
step 6
Read the value of sin(55)sin(55^\circ) from the vertical axis of the graph
[question 1] Answer
C
Key Concept
Graphical representation of sine function
Explanation
To find the sine of an angle using a graph, plot the known values and use the curve to estimate values between known points.
Solution by Steps
step 2
The calculator provides the exact value of sin(55)sin(55^\circ) as well as the equivalent cos(35)cos(35^\circ)
step 3
The value of sin(55)sin(55^\circ) is approximately 0.819152
[question 2] Answer
B
Key Concept
Sine of an angle
Explanation
The sine of an angle can be found using a calculator, which provides an exact or approximate value.
Solution by Steps
step 1
To calculate the gradient of line AB, we use the formula for the slope of a line between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), which is y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}
step 2
Substituting the given points A(2,5)A(2, 5) and B(3,4)B(-3, 4) into the slope formula, we get 542(3)\frac{5 - 4}{2 - (-3)}
step 3
Simplifying the expression, we find the slope to be 15\frac{1}{5}
1 Answer
The gradient of line AB is 15\frac{1}{5} or 0.20.2.
step 1
To find the length of AB, we use the distance formula for two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), which is (x2x1)2+(y2y1)2\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
step 2
Substituting the given points A(2,5)A(2, 5) and B(3,4)B(-3, 4) into the distance formula, we get (2(3))2+(54)2\sqrt{(2 - (-3))^2 + (5 - 4)^2}
step 3
Simplifying the expression, we find the distance to be 25+1\sqrt{25 + 1}
step 4
The distance is 26\sqrt{26}, which is approximately 5.099025.09902
2 Answer
The length of AB is 26\sqrt{26} or approximately 5.099025.09902.
Key Concept
Gradient and Distance between two points
Explanation
The gradient (or slope) of a line between two points is calculated using the change in y-coordinates divided by the change in x-coordinates. The distance between two points is found using the distance formula, which is the square root of the sum of the squares of the differences in x-coordinates and y-coordinates.
Find the equation of line A that passes through B (-2,0) and C (0,3)
Solution by Steps
step 1
To find the equation of a line, we need two points that the line passes through
step 2
We use the two given points B (-2,0) and C (0,3) to determine the slope (m) of the line
step 3
The slope m is calculated by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points
step 4
Substituting the given points into the slope formula gives m=300(2)=32m = \frac{3 - 0}{0 - (-2)} = \frac{3}{2}
step 5
With the slope and one point, we can use the point-slope form of the equation of a line: yy1=m(xx1)y - y_1 = m(x - x_1)
step 6
Substituting point B (-2,0) and the slope into the point-slope form gives y0=32(x(2))y - 0 = \frac{3}{2}(x - (-2))
step 7
Simplifying the equation gives y=32x+3y = \frac{3}{2}x + 3
Answer
The equation of line A that passes through points B (-2,0) and C (0,3) is y=32x+3y = \frac{3}{2}x + 3.
Key Concept
Finding the equation of a line using two points
Explanation
The equation of a line can be found using the slope calculated from two points and then applying the point-slope form of the line equation.
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