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The graph of the function f(x)=11+x2f(x)=\frac{1}{1+x^{2}} is called a witch of Maria Ag...
Jan 31, 2024
The graph of the function f(x)=11+x2f(x)=\frac{1}{1+x^{2}} is called a witch of Maria Agnesi. (a) Find an equation of the tangent line to the graph of this function at the point (1,12)\left(1, \frac{1}{2}\right). y= y= (b) Illustrate your solution to part (a) by graphing the function and the tangent line in the same viewing window.
Generated Graph
Solution by Steps
step 1
To find the equation of the tangent line, we first need the derivative of the function at the point of tangency
step 2
The derivative of f(x)=11+x2 f(x) = \frac{1}{1+x^2} is f(x)=2x(1+x2)2 f'(x) = -\frac{2x}{(1+x^2)^2} as per the asksia-ll calculation
step 3
Evaluate the derivative at x=1 x = 1 to find the slope of the tangent line: f(1)=2(1)(1+12)2=24=12 f'(1) = -\frac{2(1)}{(1+1^2)^2} = -\frac{2}{4} = -\frac{1}{2}
step 4
Use the point-slope form of a line with point (1,12) (1, \frac{1}{2}) and slope 12 -\frac{1}{2} : y12=12(x1) y - \frac{1}{2} = -\frac{1}{2}(x - 1)
step 5
Simplify the equation of the tangent line to get y=12x+1 y = -\frac{1}{2}x + 1
Answer
y=12x+1 y = -\frac{1}{2}x + 1
Key Concept
Finding the equation of a tangent line
Explanation
The equation of the tangent line to a curve at a given point is found using the derivative of the function at that point to determine the slope, and then applying the point-slope form of a line.
Solution by Steps
step 6
To illustrate the solution, plot the function f(x)=11+x2 f(x) = \frac{1}{1+x^2} and the tangent line y=12x+1 y = -\frac{1}{2}x + 1 on the same graph
Answer
The graph should show the curve f(x)=11+x2 f(x) = \frac{1}{1+x^2} with the tangent line y=12x+1 y = -\frac{1}{2}x + 1 intersecting it at the point (1,12) (1, \frac{1}{2}) .
Key Concept
Graphing a function and its tangent line
Explanation
The graph provides a visual representation of the function and its tangent line, showing the point of tangency and the slope of the tangent line at that point.
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