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Problem 1 Consider the random trial of rolling a fair die until a 6 is rolled, ...
Sep 10, 2024
Problem 1 Consider the random trial of rolling a fair die until a 6 is rolled, and counting how many tries this takes. a) What is the sample space? b) Given a positive integer n, what is the probability it take n tries to roll and n? c) Define the event A = “it takes an odd number of tries”. Find P(A).
Solution by Steps
step 1
The sample space for rolling a fair die consists of all possible outcomes when rolling the die. The possible outcomes are: {1,2,3,4,5,6} \{1, 2, 3, 4, 5, 6\} . Thus, the sample space is S={1,2,3,4,5,6} S = \{1, 2, 3, 4, 5, 6\} with a total of 6 outcomes
step 2
The probability of rolling a 6 on the nth try can be modeled as a geometric distribution. The probability of success (rolling a 6) is p=16 p = \frac{1}{6} and the probability of failure (not rolling a 6) is q=56 q = \frac{5}{6} . The probability that it takes exactly n n tries to roll a 6 is given by: P(X=n)=qn1p=(56)n116 P(X = n) = q^{n-1} \cdot p = \left(\frac{5}{6}\right)^{n-1} \cdot \frac{1}{6}
step 3
To find the probability P(A) P(A) that it takes an odd number of tries to roll a 6, we sum the probabilities for all odd n n : P(A)=P(X=1)+P(X=3)+P(X=5)+=k=0P(X=2k+1)=k=0(56)2k16 P(A) = P(X = 1) + P(X = 3) + P(X = 5) + \ldots = \sum_{k=0}^{\infty} P(X = 2k+1) = \sum_{k=0}^{\infty} \left(\frac{5}{6}\right)^{2k} \cdot \frac{1}{6} This is a geometric series with first term 16 \frac{1}{6} and common ratio (56)2 \left(\frac{5}{6}\right)^2
step 4
The sum of the infinite geometric series is given by: S=a1r=161(56)2=1612536=161136=611 S = \frac{a}{1 - r} = \frac{\frac{1}{6}}{1 - \left(\frac{5}{6}\right)^2} = \frac{\frac{1}{6}}{1 - \frac{25}{36}} = \frac{\frac{1}{6}}{\frac{11}{36}} = \frac{6}{11} Thus, P(A)=611 P(A) = \frac{6}{11}
Answer
The sample space is S={1,2,3,4,5,6} S = \{1, 2, 3, 4, 5, 6\} , the probability of rolling a 6 on the nth try is P(X=n)=(56)n116 P(X = n) = \left(\frac{5}{6}\right)^{n-1} \cdot \frac{1}{6} , and P(A)=611 P(A) = \frac{6}{11}
Key Concept
The concept of probability in a geometric distribution, particularly in the context of rolling a die until a specific outcome occurs.
Explanation
The solution involves understanding the sample space, calculating the probability of a specific outcome on a given trial, and summing probabilities for an infinite series to find the probability of an event occurring in an odd number of tries.
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