Is the "Maximum" function any kind of homogeneous or subhomogeneous?
Analysis...
Jan 29, 2024
Is the "Maximum" function any kind of homogeneous or subhomogeneous?
Analysis
Say M is a map from R∧2 to R,M(x,y)=max(x,y), intentionally with no absolute values.
Then, are there properties like M(ax,ay)=a∗max(x,y) or <=a^{*} \max (x, y) ?
I can't find a reference anywhere either way, I'm hoping the max function has some kind of semi-homogeneous property at least.
I'm most interested in what happens with -1 , like if I have M(−x,−y). How does this compare to the original max (x,y) ?
Solution by Steps
step 1
To determine if the function M(x,y)=max(x,y) is homogeneous, we need to check if it satisfies the condition M(ax,ay)=aM(x,y) for all a∈R and for all (x,y)∈R2
step 2
Let's consider the case when x > y . Then M(x,y)=x and M(ax,ay)=ax. If a is positive, M(ax,ay)=ax=aM(x,y), which satisfies the homogeneity condition
step 3
Now consider the case when y > x . Then M(x,y)=y and M(ax,ay)=ay. If a is positive, M(ax,ay)=ay=aM(x,y), which also satisfies the homogeneity condition
step 4
However, if a is negative, the function does not satisfy the homogeneity condition because the max function will switch the argument it takes the maximum over if both x and y change sign
step 5
For example, if M(x,y)=x because x > y , then for a < 0 , M(ax,ay) could be ay if |ay| > |ax| , which is not equal to aM(x,y)
step 6
Therefore, the function M(x,y)=max(x,y) is not homogeneous. However, it is positively homogeneous for a > 0 because it satisfies the condition M(ax,ay)=aM(x,y) in that case
Answer
The function M(x,y)=max(x,y) is not homogeneous, but it is positively homogeneous for positive scaling factors.
Key Concept
Homogeneity of a function
Explanation
A function is homogeneous if it satisfies the condition f(ax,ay)=anf(x,y) for all a∈R and for all (x,y)∈R2, where n is the degree of homogeneity. The max function does not satisfy this condition for negative a, but it does for positive a, making it positively homogeneous for positive scaling factors.