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If V (t) is the value of an investment product at time t, where t is measured in...
Nov 27, 2024
If V (t) is the value of an investment product at time t, where t is measured in years, the instantaneous log-return at time t is defined as p(t)=d/dt(In(V(t)) The company which is selling the investment product would like to give investors an incentive to hold on to the product. For this reason, they ensure that the log-return is a strictly increasing function of time. Question 1 A twice differentiable function f(t) is said to be convex if f"(t) > 0 for all t. If p'(t) > 0 it is clear that In(V) is a convex function of t. Does this also imply that V is a convex function of t?
Solution by Steps
step 1
The instantaneous log-return is defined as p(t)=ddt(ln(V(t))) p(t) = \frac{d}{dt}(\ln(V(t))) . Since p'(t) > 0 , it indicates that p(t) p(t) is increasing
step 2
If p'(t) > 0 , then p(t) p(t) is a strictly increasing function, which implies that ln(V(t)) \ln(V(t)) is convex
step 3
The second derivative test for convexity states that if f''(t) > 0 , then f(t) f(t) is convex. Here, p'(t) > 0 implies that V(t) V(t) is also increasing
step 4
However, to determine if V(t) V(t) is convex, we need to check if V''(t) > 0 . Since p(t) p(t) being increasing does not guarantee V(t) V(t) is convex, we cannot conclude this without further information
Answer
No, p'(t) > 0 does not necessarily imply that V(t) V(t) is convex without additional information about the second derivative of V(t) V(t) .
Key Concept
Convexity of functions and the relationship between derivatives.
Explanation
While p'(t) > 0 indicates that the log-return is increasing, it does not directly imply that the original function V(t) V(t) is convex without examining its second derivative.
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