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Find the slope of the tangent to the curve y=3x22x+1y = 3x^2 - 2x + 1 at x=1x = 1.
Apr 22, 2024
Find the slope of the tangent to the curve y=3x22x+1y = 3x^2 - 2x + 1 at x=1x = 1.
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Solution by Steps
step 1
To find the slope of the tangent line to the curve y=3x22x+1y = 3x^2 - 2x + 1 at a specific point, we need to compute the derivative of yy with respect to xx
step 2
The derivative of yy with respect to xx is y=dydx=6x2y' = \frac{dy}{dx} = 6x - 2
step 3
To find the slope at x=1x = 1, we substitute 11 into the derivative: y(1)=6(1)2y'(1) = 6(1) - 2
step 4
Simplifying gives us the slope at x=1x = 1: y(1)=62=4y'(1) = 6 - 2 = 4
Answer
The slope of the tangent to the curve at x=1x = 1 is 44.
Key Concept
Finding the slope of a tangent line at a point
Explanation
The slope of the tangent line to a curve at a given point is the value of the derivative of the curve's equation evaluated at that point.
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