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Find the slope of the tangent to the curve
y
=
3
x
2
−
2
x
+
1
y = 3x^2 - 2x + 1
y
=
3
x
2
−
2
x
+
1
at
x
=
1
x = 1
x
=
1
.
Apr 22, 2024
Find the slope of the tangent to the curve
y
=
3
x
2
−
2
x
+
1
y = 3x^2 - 2x + 1
y
=
3
x
2
−
2
x
+
1
at
x
=
1
x = 1
x
=
1
.
Generated Graph
Solution by Steps
step 1
To find the slope of the tangent line to the curve
y
=
3
x
2
−
2
x
+
1
y = 3x^2 - 2x + 1
y
=
3
x
2
−
2
x
+
1
at a specific point, we need to compute the derivative of
y
y
y
with respect to
x
x
x
step 2
The derivative of
y
y
y
with respect to
x
x
x
is
y
′
=
d
y
d
x
=
6
x
−
2
y' = \frac{dy}{dx} = 6x - 2
y
′
=
d
x
d
y
=
6
x
−
2
step 3
To find the slope at
x
=
1
x = 1
x
=
1
, we substitute
1
1
1
into the derivative:
y
′
(
1
)
=
6
(
1
)
−
2
y'(1) = 6(1) - 2
y
′
(
1
)
=
6
(
1
)
−
2
step 4
Simplifying gives us the slope at
x
=
1
x = 1
x
=
1
:
y
′
(
1
)
=
6
−
2
=
4
y'(1) = 6 - 2 = 4
y
′
(
1
)
=
6
−
2
=
4
Answer
The slope of the tangent to the curve at
x
=
1
x = 1
x
=
1
is
4
4
4
.
Key Concept
Finding the slope of a tangent line at a point
Explanation
The slope of the tangent line to a curve at a given point is the value of the derivative of the curve's equation evaluated at that point.
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