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Find the slope of the tangent to the curve y=3x22x+1y = 3x^2 - 2x + 1 at x=1x = 1.
Feb 4, 2024
Find the slope of the tangent to the curve y=3x22x+1y = 3x^2 - 2x + 1 at x=1x = 1.
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Solution by Steps
step 1
To find the slope of the tangent line to the curve y=3x22x+1 y = 3x^2 - 2x + 1 at x=1 x = 1 , we need to compute the derivative of y y with respect to x x
step 2
The derivative of y y with respect to x x is dydx=6x2 \frac{dy}{dx} = 6x - 2
step 3
Evaluating the derivative at x=1 x = 1 gives us dydx=6(1)2=4 \frac{dy}{dx} = 6(1) - 2 = 4
step 4
Therefore, the slope of the tangent line at x=1 x = 1 is 4
Answer
The slope of the tangent to the curve at x=1 x = 1 is 4.
Key Concept
Finding the slope of a tangent line to a curve at a given point
Explanation
The slope of the tangent line to a curve at a particular point is found by evaluating the derivative of the curve's equation at that point.
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