Logo

AskSia

Plus

Find the equation of the line that is parallel to the line 2y+6x=4 and passes th...
Jul 23, 2024
Find the equation of the line that is parallel to the line 2y+6x=4 and passes through the point (-1,5).
Solution by Steps
step 1
To find the slope of the line given by the equation 2y+6x=42y + 6x = 4, we first rewrite it in slope-intercept form y=mx+by = mx + b
step 2
Starting with 2y+6x=42y + 6x = 4, we solve for yy: 2y=6x+4 2y = -6x + 4 y=3x+2 y = -3x + 2
step 3
The slope mm of the line is 3-3
step 4
To find the equation of a line parallel to y=3x+2y = -3x + 2 that passes through the point (1,5)(-1, 5), we use the point-slope form of the equation of a line: yy1=m(xx1) y - y_1 = m(x - x_1)
step 5
Substituting m=3m = -3 and the point (1,5)(-1, 5) into the point-slope form: y5=3(x+1) y - 5 = -3(x + 1)
step 6
Simplifying the equation: y5=3x3 y - 5 = -3x - 3 y=3x+2 y = -3x + 2
Answer
The equation of the line that is parallel to 2y+6x=42y + 6x = 4 and passes through the point (1,5)(-1, 5) is y=3x+2y = -3x + 2.
Key Concept
Parallel lines have the same slope.
Explanation
To find the equation of a line parallel to a given line, we use the same slope and apply the point-slope form with the given point.
© 2023 AskSia.AI all rights reserved