Logo

AskSia

Plus

Find the derivative of y=11x37x23xy=\sqrt{11 x^{3}-7 x^{2}-\frac{3}{x}}. A $y^{\prime}=\...
Feb 15, 2024
Find the derivative of y=11x37x23xy=\sqrt{11 x^{3}-7 x^{2}-\frac{3}{x}}. A y=33x214x+3x2211x37x23xy^{\prime}=\frac{33 x^{2}-14 x+\frac{3}{x^{2}}}{2 \sqrt{11 x^{3}-7 x^{2}-\frac{3}{x}}} B y=11x47x33233x414x3+3y^{\prime}=\frac{11 x^{4}-7 x^{3}-3}{2 \sqrt{33 x^{4}-14 x^{3}+3}} C y=1233x214x3y^{\prime}=\frac{1}{2} \sqrt{33 x^{2}-14 x-3} D y=1233x214x+3x2y^{\prime}=\frac{1}{2} \sqrt{33 x^{2}-14 x+\frac{3}{x^{2}}} Ey=(332x27x+32x2)11x37x23x\mathrm{E} \circ y^{\prime}=\left(\frac{33}{2} x^{2}-7 x+\frac{3}{2 x^{2}}\right) \sqrt{11 x^{3}-7 x^{2}-\frac{3}{x}}
Generated Graph
Solution by Steps
step 2
The derivative of the inside function 11x37x23x 11x^3 - 7x^2 - \frac{3}{x} is 33x214x+3x2 33x^2 - 14x + \frac{3}{x^2}
step 3
The derivative of the outside function u \sqrt{u} with respect to u u is 12u \frac{1}{2\sqrt{u}}
step 4
Applying the chain rule, we multiply the derivative of the inside by the derivative of the outside function
step 5
The final derivative is y=33x214x+3x2211x37x23x y' = \frac{33x^2 - 14x + \frac{3}{x^2}}{2\sqrt{11x^3 - 7x^2 - \frac{3}{x}}}
A
Key Concept
Chain Rule
Explanation
To differentiate a composite function, apply the chain rule by taking the derivative of the outer function and multiplying it by the derivative of the inner function.
© 2023 AskSia.AI all rights reserved