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Find the antiderivative of f(x)=3x2f(x) = 3x^2.
Nov 21, 2023
Find the antiderivative of f(x)=3x2f(x) = 3x^2.
Here is a Step-by-Step solution: #step 1#
To find the antiderivative of a function, we need to determine the function whose derivative gives us the original function. In this case, we are looking for a function F(x)F(x) such that F(x)=3x2F'(x) = 3x^2.
#step 2#
The antiderivative of xnx^n where nn is a real number and n1n \neq -1, is given by xn+1n+1+C\frac{x^{n+1}}{n+1} + C, where CC is the constant of integration.
#step 3#
Applying the antiderivative formula to 3x23x^2, we increase the exponent by 1 to get x3x^3 and then divide by the new exponent, which is 3. We also multiply by the coefficient, which is 3, and add the constant of integration CC.
#step 4#
The antiderivative of 3x23x^2 is therefore: F(x)=3x2+12+1+C=x3+CF(x) = \frac{3x^{2+1}}{2+1} + C = x^3 + C
Answer
The antiderivative of f(x)=3x2f(x) = 3x^2 is F(x)=x3+CF(x) = x^3 + C, where CC is the constant of integration.
Key Concept
Antiderivative of a Power Function
Explanation
The antiderivative of xnx^n is xn+1n+1+C\frac{x^{n+1}}{n+1} + C, which applies to f(x)=3x2f(x) = 3x^2 to find the antiderivative F(x)=x3+CF(x) = x^3 + C.
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