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Determine the area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2.
Nov 16, 2023
Determine the area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2.
Here is a Step-by-Step solution: #step 1#
To determine the area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2, we will set up the integral from the lower bound of x=2x = -2 to the upper bound of x=2x = 2.
#step 2#
The integral that represents the area under the curve is given by: 22(4x2)dx\int_{-2}^{2} (4 - x^2) \, dx
#step 3#
We will now calculate the integral. To do this, we find the antiderivative of the function 4x24 - x^2.
#step 4#
The antiderivative of 4x24 - x^2 is 4xx334x - \frac{x^3}{3}. We will evaluate this antiderivative at the bounds x=2x = 2 and x=2x = -2 and subtract the results.
#step 5#
Evaluating the antiderivative at the bounds gives us: [4xx33]22=(4(2)233)(4(2)(2)33)\left[4x - \frac{x^3}{3}\right]_{-2}^{2} = \left(4(2) - \frac{2^3}{3}\right) - \left(4(-2) - \frac{(-2)^3}{3}\right)
#step 6#
Simplifying the expression, we get: (883)(8+83)=883+883=16163=483163=323\left(8 - \frac{8}{3}\right) - \left(-8 + \frac{8}{3}\right) = 8 - \frac{8}{3} + 8 - \frac{8}{3} = 16 - \frac{16}{3} = \frac{48}{3} - \frac{16}{3} = \frac{32}{3}
Answer
The area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2 is 323\frac{32}{3} square units.
Key Concept
The area under a curve between two points on the x-axis can be found by evaluating the definite integral of the function between those two points.
Explanation
The definite integral of the function 4x24 - x^2 from x=2x = -2 to x=2x = 2 represents the total area under the curve and above the x-axis between these points. By finding the antiderivative and evaluating it at the upper and lower bounds, we can calculate this area. The symmetry of the function about the y-axis simplifies the calculation, as the areas from x=2x = -2 to x=0x = 0 and from x=0x = 0 to x=2x = 2 are equal. The final result is 323\frac{32}{3} square units.
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