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Determine the area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2.
Jan 22, 2024
Determine the area under the curve y=4x2y = 4 - x^2 from x=2x = -2 to x=2x = 2.
Generated Graph
Solution by Steps
step 1
To find the area under the curve y=4x2 y = 4 - x^2 from x=2 x = -2 to x=2 x = 2 , we need to evaluate the definite integral 22(4x2)dx \int_{-2}^{2} (4 - x^2) \, dx
step 2
The antiderivative of 4x2 4 - x^2 is 4xx33 4x - \frac{x^3}{3}
step 3
We evaluate the antiderivative at the upper and lower limits of the integral and subtract: [4xx33]22 \left[ 4x - \frac{x^3}{3} \right]_{-2}^{2}
step 4
Plugging in the upper limit, we get 4(2)(2)33=883 4(2) - \frac{(2)^3}{3} = 8 - \frac{8}{3}
step 5
Plugging in the lower limit, we get 4(2)(2)33=8+83 4(-2) - \frac{(-2)^3}{3} = -8 + \frac{8}{3}
step 6
Subtracting the value at the lower limit from the value at the upper limit gives us (883)(8+83)=883+883 \left( 8 - \frac{8}{3} \right) - \left( -8 + \frac{8}{3} \right) = 8 - \frac{8}{3} + 8 - \frac{8}{3}
step 7
Simplifying the expression, we get 16163=483163=323 16 - \frac{16}{3} = \frac{48}{3} - \frac{16}{3} = \frac{32}{3}
Answer
323 \frac{32}{3} or approximately 10.667
Key Concept
Definite Integral as Area Under the Curve
Explanation
The definite integral of a function from a to b gives the area under the curve of the function between x = a and x = b, provided the function is continuous on [a, b].
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