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Compute the volume of the solid obtained by rotating the region bounded by $y = ...
Jan 3, 2024
Compute the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis.
Solution by Steps
step 1
Identify the method of disks/washers to compute the volume of the solid of revolution
step 2
Set up the integral for the volume using the washer method, where the outer radius R(y) R(y) is y \sqrt{y} and the inner radius r(y) r(y) is 0, since the region is rotated about the y-axis
step 3
Write the volume integral: V=π04(y)2dy V = \pi \int_{0}^{4} (\sqrt{y})^2 dy
step 4
Simplify the integral: V=π04ydy V = \pi \int_{0}^{4} y dy
step 5
Compute the integral: V=π[y22]04 V = \pi \left[ \frac{y^2}{2} \right]_{0}^{4}
step 6
Evaluate the definite integral: V=π(422022) V = \pi \left( \frac{4^2}{2} - \frac{0^2}{2} \right)
step 7
Simplify to find the volume: V=π(162)=8π V = \pi \left( \frac{16}{2} \right) = 8\pi
Answer
The volume of the solid obtained by rotating the region bounded by y=x2 y = x^2 , x=0 x = 0 , and y=4 y = 4 about the y-axis is 8π 8\pi cubic units.
Key Concept
Volume of a solid of revolution using the washer method
Explanation
The washer method involves integrating the area of a washer, which is the region between two concentric circles, as it revolves around an axis. In this case, the outer radius is the square root of y, and there is no inner radius since the solid is rotated around the y-axis.
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