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Compute the volume of the solid obtained by rotating the region bounded by $y = ...
May 12, 2024
Compute the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis.
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Solution by Steps
step 1
To find the volume of the solid obtained by rotating the region around the y-axis, we use the method of cylindrical shells
step 2
The formula for the volume of a cylindrical shell is V=2πabxf(x)dxV = 2\pi \int_a^b x f(x) \, dx, where f(x)f(x) is the function being rotated
step 3
In this case, f(x)=x2f(x) = x^2 and the limits of integration are from a=0a = 0 to b=2b = 2, since the region is bounded by y=4y = 4 and y=x2y = x^2 intersects y=4y = 4 at x=2x = 2
step 4
Substituting f(x)=x2f(x) = x^2 into the formula, we get V=2π02x(x2)dxV = 2\pi \int_0^2 x (x^2) \, dx
step 5
This integral simplifies to V=2π02x3dxV = 2\pi \int_0^2 x^3 \, dx
step 6
Using the power rule for integration, we find the antiderivative of x3x^3 to be x44\frac{x^4}{4}
step 7
Evaluating the definite integral from 0 to 2, we get V=2π[x44]02V = 2\pi \left[\frac{x^4}{4}\right]_0^2
step 8
Plugging in the limits of integration, we find V=2π[244044]V = 2\pi \left[\frac{2^4}{4} - \frac{0^4}{4}\right]
step 9
Simplifying, we get V=2π[164]=2π[4]V = 2\pi \left[\frac{16}{4}\right] = 2\pi [4]
step 10
Therefore, the volume of the solid is V=8πV = 8\pi
Answer
The volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis is 8π8\pi cubic units.
Key Concept
Method of Cylindrical Shells
Explanation
The method of cylindrical shells is used to compute the volume of a solid of revolution when the solid is generated by rotating a region around an axis, in this case, the y-axis. The volume is found by integrating the product of the circumference of the shell, the height of the shell, and the thickness of the shell.
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