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Compute the volume of the solid obtained by rotating the region bounded by $y = ...
Nov 21, 2023
Compute the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis.
Here is a Step-by-Step solution: #step 1#
To find the volume of the solid obtained by rotating the region bounded by the curves around the y-axis, we will use the method of disks or washers. The volume VV of the solid can be computed using the integral V=πab[R(y)]2dyV = \pi \int_{a}^{b} [R(y)]^2 dy where R(y)R(y) is the radius of the disk (or washer) at a given yy-value, and aa and bb are the bounds of integration along the y-axis.
#step 2#
The region is bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4. Since we are rotating around the y-axis, the radius of the disk at any point will be equal to the x-coordinate of the curve y=x2y = x^2. Solving for xx, we get x=yx = \sqrt{y}. The bounds of integration are from y=0y = 0 to y=4y = 4, as given by the intersection points of the curves.
#step 3#
Setting up the integral to compute the volume, we have V=π04(y)2dy=π04ydy.V = \pi \int_{0}^{4} (\sqrt{y})^2 dy = \pi \int_{0}^{4} y dy.
#step 4#
Evaluating the integral, we get V=π[y22]04=π[422022]=π[80]=8π.V = \pi \left[ \frac{y^2}{2} \right]_{0}^{4} = \pi \left[ \frac{4^2}{2} - \frac{0^2}{2} \right] = \pi \left[ 8 - 0 \right] = 8\pi.
Answer
The volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis is 8π8\pi cubic units.
Key Concept
Volume of a solid of revolution using the disk method
Explanation
The volume is found by integrating the area of circular disks along the axis of rotation, which in this case is the y-axis. The radius of each disk is determined by the x-value of the function y=x2y = x^2 at a given y-value, and the integral is evaluated between the y-bounds of the region.
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