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Compute the volume of the solid obtained by rotating the region bounded by $y = ...
Apr 18, 2024
Compute the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis.
Generated Graph
Solution by Steps
step 1
To find the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis, we use the method of cylindrical shells
step 2
The volume of a thin cylindrical shell with radius rr, height hh, and thickness Δx\Delta x is given by 2πrhΔx2\pi rh \Delta x
step 3
For the given region, the radius of the shell is r=xr = x and the height is h=x2h = x^2
step 4
The volume of the solid is the integral of the volume of the shells from x=0x = 0 to x=2x = 2, which is the boundary of the region for y=x2y = x^2 when y=4y = 4
step 5
The integral for the volume is V=022πx(x2)dxV = \int_{0}^{2} 2\pi x(x^2) dx
step 6
Simplify the integral to V=2π02x3dxV = 2\pi \int_{0}^{2} x^3 dx
step 7
Using the power rule for integration, we find V=2π[x44]02V = 2\pi \left[\frac{x^4}{4}\right]_0^2
step 8
Evaluate the integral from 00 to 22 to get V=2π[244044]V = 2\pi \left[\frac{2^4}{4} - \frac{0^4}{4}\right]
step 9
Simplify to find V=2π[164]=2π[4]=8πV = 2\pi \left[\frac{16}{4}\right] = 2\pi [4] = 8\pi
Answer
The volume of the solid is 8π8\pi cubic units.
Key Concept
Method of Cylindrical Shells
Explanation
The method of cylindrical shells is used to compute the volume of a solid of revolution when integrating along the axis of rotation. The volume is found by integrating the surface area of cylindrical shells.
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