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Compute the volume of the solid obtained by rotating the region bounded by $y = ...
Apr 7, 2024
Compute the volume of the solid obtained by rotating the region bounded by y=x2y = x^2, x=0x = 0, and y=4y = 4 about the y-axis.
Generated Graph
Solution by Steps
step 1
To find the volume of the solid obtained by rotating the region bounded by y=x2 y = x^2 , x=0 x = 0 , and y=4 y = 4 about the y-axis, we use the method of cylindrical shells
step 2
The volume of a thin cylindrical shell with radius r r , height h h , and thickness Δr \Delta r is given by 2πrhΔr 2\pi rh \Delta r
step 3
In this case, the radius r r is x x , the height h h is y=x2 y = x^2 , and Δr \Delta r is dx dx
step 4
The volume V V is the integral of the volume of the shells from x=0 x = 0 to x=2 x = 2 (since y=4 y = 4 when x=2 x = 2 )
step 5
Set up the integral for the volume: V=022πx(x2)dx V = \int_{0}^{2} 2\pi x(x^2) dx
step 6
Simplify the integral: V=022πx3dx V = \int_{0}^{2} 2\pi x^3 dx
step 7
Calculate the integral using the power rule: V=2π[x44]02 V = 2\pi \left[ \frac{x^4}{4} \right]_{0}^{2}
step 8
Evaluate the integral from x=0 x = 0 to x=2 x = 2 : V=2π[244044] V = 2\pi \left[ \frac{2^4}{4} - \frac{0^4}{4} \right]
step 9
Simplify to find the volume: V=2π[164]=2π[4]=8π V = 2\pi \left[ \frac{16}{4} \right] = 2\pi [4] = 8\pi
Answer
V=8π V = 8\pi cubic units
Key Concept
Cylindrical Shells Method
Explanation
The volume of the solid of revolution is calculated using the cylindrical shells method, which involves integrating the volume of infinitesimally thin cylindrical shells between the given bounds.
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