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Compute the area between the curves
y
=
x
2
y = x^2
y
=
x
2
and
y
=
2
x
y = 2x
y
=
2
x
.
Apr 1, 2024
Compute the area between the curves
y
=
x
2
y = x^2
y
=
x
2
and
y
=
2
x
y = 2x
y
=
2
x
.
Generated Graph
Solution by Steps
step 1
To find the area between the curves
y
=
x
2
y = x^2
y
=
x
2
and
y
=
2
x
y = 2x
y
=
2
x
, we need to set up the integral of the difference between the two functions
step 2
The points of intersection are found by setting
x
2
=
2
x
x^2 = 2x
x
2
=
2
x
, which gives us
x
=
0
x = 0
x
=
0
and
x
=
2
x = 2
x
=
2
. These will be the limits of our integral
step 3
The integral to find the area between the curves is
∫
0
2
(
2
x
−
x
2
)
d
x
\int_{0}^{2} (2x - x^2) dx
∫
0
2
(
2
x
−
x
2
)
d
x
step 4
Computing the integral, we get
∫
0
2
(
2
x
−
x
2
)
d
x
=
[
x
2
−
x
3
3
]
0
2
\int_{0}^{2} (2x - x^2) dx = \left[ x^2 - \frac{x^3}{3} \right]_{0}^{2}
∫
0
2
(
2
x
−
x
2
)
d
x
=
[
x
2
−
3
x
3
]
0
2
step 5
Evaluating the integral from 0 to 2, we get
[
2
2
−
2
3
3
]
−
[
0
2
−
0
3
3
]
=
4
−
8
3
\left[ 2^2 - \frac{2^3}{3} \right] - \left[ 0^2 - \frac{0^3}{3} \right] = 4 - \frac{8}{3}
[
2
2
−
3
2
3
]
−
[
0
2
−
3
0
3
]
=
4
−
3
8
step 6
Simplifying the result, we find the area to be
4
−
8
3
=
12
3
−
8
3
=
4
3
4 - \frac{8}{3} = \frac{12}{3} - \frac{8}{3} = \frac{4}{3}
4
−
3
8
=
3
12
−
3
8
=
3
4
Answer
The area between the curves
y
=
x
2
y = x^2
y
=
x
2
and
y
=
2
x
y = 2x
y
=
2
x
is
4
3
\frac{4}{3}
3
4
square units.
Key Concept
Area between two curves
Explanation
The area between two curves is found by integrating the difference of the functions over the interval defined by their points of intersection.
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