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Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Apr 28, 2024
Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Generated Graph
Solution by Steps
step 1
To find the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4, we need to evaluate the definite integral 14x3dx\int_{1}^{4} x^3 \, dx
step 2
The antiderivative of x3x^3 is x44\frac{x^4}{4}, so we use the Fundamental Theorem of Calculus to evaluate the integral at the upper and lower limits
step 3
We substitute x=4x = 4 into the antiderivative to get 444=2564=64\frac{4^4}{4} = \frac{256}{4} = 64
step 4
We then substitute x=1x = 1 into the antiderivative to get 144=14\frac{1^4}{4} = \frac{1}{4}
step 5
Subtracting the value at x=1x = 1 from the value at x=4x = 4, we get 6414=256414=255464 - \frac{1}{4} = \frac{256}{4} - \frac{1}{4} = \frac{255}{4}
Answer
2554=63.75\frac{255}{4} = 63.75
Key Concept
Definite Integral Evaluation
Explanation
The area under the curve from x=1x = 1 to x=4x = 4 is found by evaluating the definite integral of the function x3x^3, which involves finding the antiderivative and then applying the limits of integration.
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