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Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Nov 24, 2023
Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Here is a Step-by-Step solution: #step 1#
Set up the definite integral for the area under the curve from x=1x = 1 to x=4x = 4.
#step 2#
The integral is 14x3dx\int_{1}^{4} x^3 \, dx.
#step 3#
Find the antiderivative of x3x^3, which is x44\frac{x^4}{4}.
#step 4#
Evaluate the antiderivative from x=1x = 1 to x=4x = 4: [x44]14\left[\frac{x^4}{4}\right]_{1}^{4}.
#step 5#
Substitute the limits of integration: 444144\frac{4^4}{4} - \frac{1^4}{4}.
#step 6#
Calculate the result: 256414\frac{256}{4} - \frac{1}{4}.
#step 7#
Simplify the expression: 641464 - \frac{1}{4}.
#step 8#
Final calculation: 6414=63.7564 - \frac{1}{4} = 63.75.
Answer
The area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4 is 63.7563.75 square units.
Key Concept
The definite integral of a function from a to b gives the area under the curve of the function between x = a and x = b.
Explanation
⚹By integrating the function y=x3y = x^3 from x=1x = 1 to x=4x = 4, we calculated the area under the curve. The antiderivative of x3x^3 is x44\frac{x^4}{4}, and evaluating this from x=1x = 1 to x=4x = 4 gives us the area, which is 63.7563.75 square units.
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