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Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Apr 30, 2024
Calculate the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4.
Generated Graph
Solution by Steps
step 1
To find the area under the curve y=x3y = x^3 from x=1x = 1 to x=4x = 4, we need to evaluate the definite integral 14x3dx\int_{1}^{4} x^3 \, dx
step 2
The antiderivative of x3x^3 is x44\frac{x^4}{4}
step 3
We evaluate the antiderivative at the upper and lower limits of integration and subtract: [x44]14=444144\left[\frac{x^4}{4}\right]_{1}^{4} = \frac{4^4}{4} - \frac{1^4}{4}
step 4
Simplifying the expression gives us 256414=6414\frac{256}{4} - \frac{1}{4} = 64 - \frac{1}{4}
step 5
The final result is 6414=256414=255464 - \frac{1}{4} = \frac{256}{4} - \frac{1}{4} = \frac{255}{4}
Answer
2554=63.75\frac{255}{4} = 63.75
Key Concept
Definite Integral
Explanation
The area under the curve from x=1x = 1 to x=4x = 4 is found by evaluating the definite integral of the function x3x^3 over the interval [1, 4].
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