COMP9020 2024 Term 2 - Problem Set 2 of 8
Deadline - Monday June 17, 09:00.
Ans...
Jun 16, 2024
Solution by Steps
step 1
Let H(x) represent "x is hungry" and let A represent Alice
step 2
The statement "Either Alice is hungry or everyone is hungry" can be written as: H(A)∨∀xH(x)
Answer
H(A)∨∀xH(x)
Key Concept
Predicate Logic Translation
Explanation
We use H(x) to denote "x is hungry" and A for Alice, then translate the statement directly.
Question 2
Translate the following into fully symbolic predicate logic - "If someone is tall then Alice is tall".
step 1
Let T(x) represent "x is tall" and let A represent Alice
step 2
The statement "If someone is tall then Alice is tall" can be written as: ∃xT(x)→T(A)
Answer
∃xT(x)→T(A)
Key Concept
Predicate Logic Translation
Explanation
We use T(x) to denote "x is tall" and A for Alice, then translate the statement directly.
Question 3
Translate the following into fully symbolic predicate logic - "If all students are studying hard, then everyone is happy".
step 1
Let S(x) represent "x is studying hard" and H(x) represent "x is happy"
step 2
The statement "If all students are studying hard, then everyone is happy" can be written as: ∀xS(x)→∀xH(x)
Answer
∀xS(x)→∀xH(x)
Key Concept
Predicate Logic Translation
Explanation
We use S(x) to denote "x is studying hard" and H(x) to denote "x is happy", then translate the statement directly.
Question 4
Is the following wff a logical truth? If so, then justify your answer in your own words. If not, then provide a countermodel:
- ∃xPx↔(∃xPx→∃xQx)
step 1
Analyze the given wff: ∃xPx↔(∃xPx→∃xQx)
step 2
The left side ∃xPx asserts the existence of some x such that P(x) is true
step 3
The right side (∃xPx→∃xQx) asserts that if there exists some x such that P(x) is true, then there exists some x such that Q(x) is true
step 4
If ∃xPx is true, then (∃xPx→∃xQx) must also be true if ∃xQx is true
step 5
If ∃xPx is false, then (∃xPx→∃xQx) is true by the definition of implication
step 6
Therefore, ∃xPx↔(∃xPx→∃xQx) is always true, making it a logical truth
Answer
Logical Truth
Key Concept
Logical Equivalence
Explanation
The given wff is always true regardless of the truth values of P(x) and Q(x), making it a logical truth.
Question 5
Is the following argument valid? If so, justify your answer in your own words. If not, then provide a countermodel:
1. ∀x 2. ∴amp;(Px→Qx)amp;∼Qaamp;∼Pa
step 1
The first premise ∀x(P(x)→Q(x)) states that for all x, if P(x) is true, then Q(x) must also be true
step 2
The second premise ∼Q(a) states that Q(a) is false
step 3
To determine the validity, we need to check if ∼P(a) logically follows from the premises
step 4
From ∀x(P(x)→Q(x)), we know that if P(a) were true, then Q(a) would have to be true
step 5
Since Q(a) is false, P(a) cannot be true (otherwise it would contradict the first premise)
step 6
Therefore, ∼P(a) must be true, making the argument valid
Answer
Valid
Key Concept
Modus Tollens
Explanation
The argument uses the logical rule of Modus Tollens, which states that if P→Q and ∼Q are true, then ∼P must also be true.