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COMP9020 2024 Term 2 - Problem Set 2 of 8 Deadline - Monday June 17, 09:00. Ans...
Jun 16, 2024
Solution by Steps
step 1
Let H(x)H(x) represent "x is hungry" and let AA represent Alice
step 2
The statement "Either Alice is hungry or everyone is hungry" can be written as: H(A)xH(x)H(A) \lor \forall x \, H(x)
Answer
H(A)xH(x)H(A) \lor \forall x \, H(x)
Key Concept
Predicate Logic Translation
Explanation
We use H(x)H(x) to denote "x is hungry" and AA for Alice, then translate the statement directly.
Question 2 Translate the following into fully symbolic predicate logic - "If someone is tall then Alice is tall".
step 1
Let T(x)T(x) represent "x is tall" and let AA represent Alice
step 2
The statement "If someone is tall then Alice is tall" can be written as: xT(x)T(A)\exists x \, T(x) \rightarrow T(A)
Answer
xT(x)T(A)\exists x \, T(x) \rightarrow T(A)
Key Concept
Predicate Logic Translation
Explanation
We use T(x)T(x) to denote "x is tall" and AA for Alice, then translate the statement directly.
Question 3 Translate the following into fully symbolic predicate logic - "If all students are studying hard, then everyone is happy".
step 1
Let S(x)S(x) represent "x is studying hard" and H(x)H(x) represent "x is happy"
step 2
The statement "If all students are studying hard, then everyone is happy" can be written as: xS(x)xH(x)\forall x \, S(x) \rightarrow \forall x \, H(x)
Answer
xS(x)xH(x)\forall x \, S(x) \rightarrow \forall x \, H(x)
Key Concept
Predicate Logic Translation
Explanation
We use S(x)S(x) to denote "x is studying hard" and H(x)H(x) to denote "x is happy", then translate the statement directly.
Question 4 Is the following wff a logical truth? If so, then justify your answer in your own words. If not, then provide a countermodel: - xPx(xPxxQx)\exists x P x \leftrightarrow (\exists x P x \rightarrow \exists x Q x)
step 1
Analyze the given wff: xPx(xPxxQx)\exists x P x \leftrightarrow (\exists x P x \rightarrow \exists x Q x)
step 2
The left side xPx\exists x P x asserts the existence of some xx such that P(x)P(x) is true
step 3
The right side (xPxxQx)(\exists x P x \rightarrow \exists x Q x) asserts that if there exists some xx such that P(x)P(x) is true, then there exists some xx such that Q(x)Q(x) is true
step 4
If xPx\exists x P x is true, then (xPxxQx)(\exists x P x \rightarrow \exists x Q x) must also be true if xQx\exists x Q x is true
step 5
If xPx\exists x P x is false, then (xPxxQx)(\exists x P x \rightarrow \exists x Q x) is true by the definition of implication
step 6
Therefore, xPx(xPxxQx)\exists x P x \leftrightarrow (\exists x P x \rightarrow \exists x Q x) is always true, making it a logical truth
Answer
Logical Truth
Key Concept
Logical Equivalence
Explanation
The given wff is always true regardless of the truth values of P(x)P(x) and Q(x)Q(x), making it a logical truth.
Question 5 Is the following argument valid? If so, justify your answer in your own words. If not, then provide a countermodel:  1. xamp;(PxQx) 2. amp;Qaamp;Pa \text { 1. } \begin{aligned} \forall x & (P x \rightarrow Q x) \\ \text { 2. } & \sim Q a \\ \therefore & \sim P a \end{aligned}
step 1
The first premise x(P(x)Q(x))\forall x (P(x) \rightarrow Q(x)) states that for all xx, if P(x)P(x) is true, then Q(x)Q(x) must also be true
step 2
The second premise Q(a)\sim Q(a) states that Q(a)Q(a) is false
step 3
To determine the validity, we need to check if P(a)\sim P(a) logically follows from the premises
step 4
From x(P(x)Q(x))\forall x (P(x) \rightarrow Q(x)), we know that if P(a)P(a) were true, then Q(a)Q(a) would have to be true
step 5
Since Q(a)Q(a) is false, P(a)P(a) cannot be true (otherwise it would contradict the first premise)
step 6
Therefore, P(a)\sim P(a) must be true, making the argument valid
Answer
Valid
Key Concept
Modus Tollens
Explanation
The argument uses the logical rule of Modus Tollens, which states that if PQP \rightarrow Q and Q\sim Q are true, then P\sim P must also be true.
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