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A train travels a distance of 480 km at a uniform speed if the speed had been 8 ...
Jul 21, 2024
A train travels a distance of 480 km at a uniform speed if the speed had been 8 km per hour less then it would have taken 3 hours more to cover same distance we need to find speed of the train
Generated Graph
Solution by Steps
step 1
Let the speed of the train be xx km/h
step 2
The time taken to travel 480 km at xx km/h is 480x\frac{480}{x} hours
step 3
If the speed is 8 km/h less, the speed is (x8)(x - 8) km/h
step 4
The time taken to travel 480 km at (x8)(x - 8) km/h is 480x8\frac{480}{x - 8} hours
step 5
According to the problem, the difference in time is 3 hours: 480x8480x=3\frac{480}{x - 8} - \frac{480}{x} = 3
step 6
Multiply both sides by x(x8)x(x - 8) to clear the denominators: 480x480(x8)=3x(x8)480x - 480(x - 8) = 3x(x - 8)
step 7
Simplify the equation: 480x480x+3840=3x224x480x - 480x + 3840 = 3x^2 - 24x
step 8
Combine like terms: 3840=3x224x3840 = 3x^2 - 24x
step 9
Rearrange the equation: 3x224x3840=03x^2 - 24x - 3840 = 0
step 10
Divide the entire equation by 3: x28x1280=0x^2 - 8x - 1280 = 0
step 11
Solve the quadratic equation using the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=8b = -8, and c=1280c = -1280
step 12
Calculate the discriminant: b24ac=(8)24(1)(1280)=64+5120=5184b^2 - 4ac = (-8)^2 - 4(1)(-1280) = 64 + 5120 = 5184
step 13
Find the roots: x=8±51842=8±722x = \frac{8 \pm \sqrt{5184}}{2} = \frac{8 \pm 72}{2}
step 14
The solutions are x=802=40x = \frac{80}{2} = 40 and x=642=32x = \frac{-64}{2} = -32
step 15
Since speed cannot be negative, the speed of the train is x=40x = 40 km/h
Answer
The speed of the train is 40 km/h
Key Concept
Solving quadratic equations
Explanation
We used the quadratic formula to solve for the speed of the train, ensuring that the solution is physically meaningful (i.e., non-negative).
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