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A biomass gasifier converts
500
k
g
500 \mathrm{~kg}
500
kg
of biomass into producer gas. Th...
Jun 15, 2024
Generated Graph
Solution by Steps
step 1
Calculate the total energy content of the biomass using its heating value:
500
kg
×
17500
kJ/kg
=
8750000
kJ
500 \, \text{kg} \times 17500 \, \text{kJ/kg} = 8750000 \, \text{kJ}
500
kg
×
17500
kJ/kg
=
8750000
kJ
step 2
Calculate the total energy content of the producer gas using its heating value:
2200
m
3
×
8500
kJ/m
3
=
18700000
kJ
2200 \, \text{m}^3 \times 8500 \, \text{kJ/m}^3 = 18700000 \, \text{kJ}
2200
m
3
×
8500
kJ/m
3
=
18700000
kJ
step 3
Calculate the mass of the producer gas using its density:
2200
m
3
×
1.29
kg/m
3
=
2838
kg
2200 \, \text{m}^3 \times 1.29 \, \text{kg/m}^3 = 2838 \, \text{kg}
2200
m
3
×
1.29
kg/m
3
=
2838
kg
step 4
Integrate the energy content of the producer gas over the given volume:
∫
0
18700000
2838
d
x
=
2838
×
18700000
=
53070600000
kJ
\int_0^{18700000} 2838 \, dx = 2838 \times 18700000 = 53070600000 \, \text{kJ}
∫
0
18700000
2838
d
x
=
2838
×
18700000
=
53070600000
kJ
step 5
Calculate the efficiency of the thermal gasification process:
53070600000
kJ
8750000
kJ
=
6.065
\frac{53070600000 \, \text{kJ}}{8750000 \, \text{kJ}} = 6.065
8750000
kJ
53070600000
kJ
=
6.065
Answer
The efficiency of the thermal gasification process is approximately 6.065.
Key Concept
Thermal Gasification Efficiency
Explanation
The efficiency is calculated by comparing the energy content of the producer gas to the energy content of the biomass.
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