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A 4 cylinder, 4 stroke marine oil engine has a cylinder diameter of 49 mm and a ...
Jan 1, 2024
The following data is available for 2-stroke diesel engine: Bore = 10 cm, stroke = 15 cm, engine speed = 1000 RPM, torque developed = 58 N-m, nm=80%, indicated thermal efficiency = 40%, calorific value of fuel = 44000 kJ/kg. Find: (a) Indicated power (b) Mean effective pressure and (c) Brake specific fuel consumption
Solution by Steps
step 1
To find the indicated power (IP), we use the formula: IP=2πNT60×nm IP = \frac{2 \pi N T}{60} \times \text{nm} where N N is the engine speed in RPM, T T is the torque in N-m, and nm \text{nm} is the mechanical efficiency
step 2
Substituting the given values into the formula: IP=2π×1000×5860×0.80 IP = \frac{2 \pi \times 1000 \times 58}{60} \times 0.80
step 3
Calculating the indicated power: IP=2π×1000×5860×0.80=61.6π W IP = \frac{2 \pi \times 1000 \times 58}{60} \times 0.80 = 61.6 \pi \text{ W}
Answer
Indicated power (IP) is approximately 193.65 W
Key Concept
Indicated power is the total power developed inside the engine cylinders
Explanation
Indicated power is calculated by considering the engine speed, torque, and mechanical efficiency. It represents the power developed by the combustion of fuel before any losses due to engine components.
step 1
To find the mean effective pressure (MEP), we use the formula: MEP=2πNTVs MEP = \frac{2 \pi N T}{V_s} where Vs V_s is the swept volume per cycle in cubic meters
step 2
The swept volume Vs V_s is calculated by: Vs=πd24×S V_s = \frac{\pi d^2}{4} \times S where d d is the bore diameter and S S is the stroke length
step 3
Substituting the given values for bore (d = 0.1 m) and stroke (S = 0.15 m): Vs=π×(0.1)24×0.15=π×0.014×0.15 V_s = \frac{\pi \times (0.1)^2}{4} \times 0.15 = \frac{\pi \times 0.01}{4} \times 0.15
step 4
Calculating the swept volume: Vs=π×0.014×0.15=0.00011775 m3 V_s = \frac{\pi \times 0.01}{4} \times 0.15 = 0.00011775 \text{ m}^3
step 5
Now, we can calculate the mean effective pressure: MEP=2π×1000×580.00011775×1000 MEP = \frac{2 \pi \times 1000 \times 58}{0.00011775 \times 1000}
step 6
Simplifying the expression for MEP: MEP=2π×580.00011775 MEP = \frac{2 \pi \times 58}{0.00011775}
step 7
Calculating the mean effective pressure: MEP=2π×580.00011775978,000 Pa MEP = \frac{2 \pi \times 58}{0.00011775} \approx 978,000 \text{ Pa}
Answer
Mean effective pressure (MEP) is approximately 978 kPa
Key Concept
Mean effective pressure is a measure of the average pressure that acts on the pistons
Explanation
MEP is calculated using the torque, engine speed, and the swept volume of the engine. It is an indication of the engine's ability to do work and is independent of engine displacement.
step 1
To find the brake specific fuel consumption (BSFC), we use the formula: BSFC=Fuel Consumption RateBrake Power BSFC = \frac{\text{Fuel Consumption Rate}}{\text{Brake Power}}
step 2
The brake power (BP) is given by: BP=2πNT60 BP = \frac{2 \pi N T}{60}
step 3
Substituting the given values into the formula for brake power: BP=2π×1000×5860=61.6π W BP = \frac{2 \pi \times 1000 \times 58}{60} = 61.6 \pi \text{ W}
step 4
The fuel consumption rate can be found from the indicated power and indicated thermal efficiency (ηi \eta_i ): Fuel Consumption Rate=IPηi×CV \text{Fuel Consumption Rate} = \frac{IP}{\eta_i \times \text{CV}} where CV \text{CV} is the calorific value of the fuel
step 5
Substituting the indicated power and given values: Fuel Consumption Rate=193.650.40×44000 \text{Fuel Consumption Rate} = \frac{193.65}{0.40 \times 44000}
step 6
Calculating the fuel consumption rate: Fuel Consumption Rate=193.65176000.011 kg/s \text{Fuel Consumption Rate} = \frac{193.65}{17600} \approx 0.011 \text{ kg/s}
step 7
Now, we can calculate the brake specific fuel consumption: BSFC=0.01161.6π×103 BSFC = \frac{0.011}{61.6 \pi \times 10^{-3}}
step 8
Simplifying the expression for BSFC: BSFC=0.01161.6π×1030.00056 kg/Ws BSFC = \frac{0.011}{61.6 \pi \times 10^{-3}} \approx 0.00056 \text{ kg/Ws}
step 9
Converting BSFC to more common units (g/kWh): BSFC=0.00056×106 g/kWh BSFC = 0.00056 \times 10^6 \text{ g/kWh}
step 10
Calculating the final value for BSFC: BSFC=0.00056×106560 g/kWh BSFC = 0.00056 \times 10^6 \approx 560 \text{ g/kWh}
Answer
Brake specific fuel consumption (BSFC) is approximately 560 g/kWh
Key Concept
Brake specific fuel consumption is a measure of the fuel efficiency of an engine
Explanation
BSFC is the amount of fuel consumed per unit of power produced by the engine. It is an important metric for comparing the efficiency of different engines or engine settings.
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