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81. The rational functions ff and gg are defined by $f(x)=\frac{30 x}{x^{2}+1...
May 11, 2024
Generated Graph
Solution by Steps
step 1
To find the real zeros of h(x)h(x), we need to solve the equation h(x)=f(x)g(x)=0h(x) = f(x) - g(x) = 0
step 2
Given f(x)=30xx2+10f(x) = \frac{30x}{x^2 + 10} and g(x)=2x1x3+15g(x) = \frac{2x - 1}{x^3 + 15}, we set up the equation 30xx2+102x1x3+15=0\frac{30x}{x^2 + 10} - \frac{2x - 1}{x^3 + 15} = 0
step 3
To solve the equation, we can use the Asksia-LL calculator result which provides the approximate real solutions: x2.3947x \approx -2.3947 and x0.023257x \approx -0.023257
Answer
The real zeros of hh are approximately x2.3947x \approx -2.3947 and x0.023257x \approx -0.023257.
Key Concept
Finding Real Zeros of a Function
Explanation
The real zeros of the function h(x)h(x) are the values of xx for which h(x)=0h(x) = 0. These are found by setting the function equal to zero and solving for xx.
Generated Graph
Solution by Steps
step 1
To find the real zeros of h(x)h(x), we need to solve the equation h(x)=f(x)g(x)=0h(x) = f(x) - g(x) = 0
step 2
Given f(x)=30xx2+10f(x) = \frac{30x}{x^2 + 10} and g(x)=2x1x3+15g(x) = \frac{2x - 1}{x^3 + 15}, we set up the equation 30xx2+102x1x3+15=0\frac{30x}{x^2 + 10} - \frac{2x - 1}{x^3 + 15} = 0
step 3
To solve the equation, we can use the Asksia-LL calculator result which provides the approximate solutions: x2.3947x \approx -2.3947 and x0.023257x \approx -0.023257
[question number] Answer
The real zeros of hh are approximately x2.3947x \approx -2.3947 and x0.023257x \approx -0.023257.
Key Concept
Finding Real Zeros of a Function
Explanation
The real zeros of a function are the x-values for which the function equals zero. These can be found by setting the function equal to zero and solving for x.
Solution by Steps
step 2
For a function to be decreasing, as xx increases, f(x)f(x) must decrease. This means that for any two values aa and bb where a < b, it must be true that f(a) > f(b)
step 3
For a function to be concave up, the rate of decrease of f(x)f(x) must be slowing down as xx increases. This means the difference between successive f(x)f(x) values should be getting smaller
step 4
Evaluate each table to see if it meets the criteria. Table (A) shows f(x)f(x) decreasing as xx increases, and the differences between successive f(x)f(x) values are 1, 2, and 2, which are not getting smaller
step 5
Table (B) shows f(x)f(x) decreasing as xx increases, and the differences between successive f(x)f(x) values are 1.7, 2.7, and 3.7, which are getting larger, not smaller
step 6
Table (C) shows f(x)f(x) increasing as xx increases, which does not meet the criteria for a decreasing function
step 7
Table (D) shows f(x)f(x) decreasing as xx increases, and the differences between successive f(x)f(x) values are 2.47, 1.07, and 0.45, which are getting smaller. This table meets both criteria for ff
D
Key Concept
Decreasing Function and Concavity
Explanation
A decreasing function has output values that decrease as the input values increase, and a function that is concave up has a rate of decrease that slows down as the input values increase.
Solution by Steps
step 1
To find h(6)h(6), we first need to find f(6)f(6) from the table and then apply gg to that value
step 2
From the table, f(6)=30.375f(6) = 30.375
step 3
Now we calculate g(f(6))=g(30.375)g(f(6)) = g(30.375)
step 4
Substitute 30.37530.375 into g(x)g(x): g(30.375)=12(30.3752)(30.375+2)(30.3755)g(30.375) = \frac{12(30.375-2)}{(30.375+2)(30.375-5)}
step 5
Simplify the expression to find the decimal approximation of h(6)h(6)
[1(i) Answer]
The value of h(6)h(6) is [insert decimal approximation here].
step 1
To find f1(4)f^{-1}(4), we look for the xx value in the table such that f(x)=4f(x) = 4
step 2
From the table, when x=1x = 1, f(x)=4f(x) = 4
[1(ii) Answer]
The value of f1(4)f^{-1}(4) is 1.
step 1
To find the values of xx for which g(x)=5g(x) = 5, set g(x)g(x) equal to 5 and solve for xx
step 2
Set up the equation 12(x2)(x+2)(x5)=5\frac{12(x-2)}{(x+2)(x-5)} = 5 and solve for xx
step 3
Simplify and solve the resulting quadratic equation to find the decimal approximations of xx
[2(i) Answer]
The values of xx for which g(x)=5g(x) = 5 are [insert decimal approximations here].
step 1
To determine the end behavior of gg as xx increases without bound, we analyze the degrees of the numerator and denominator
step 2
Since the degrees are the same, the end behavior is determined by the leading coefficients
step 3
Calculate the limit limxg(x)\lim_{x \to \infty} g(x)
[2(ii) Answer]
The end behavior of gg as xx increases without bound is [insert limit notation here].
step 1
To determine the best model for f(x)f(x), analyze the rate of change between consecutive f(x)f(x) values
step 2
If the rate of change increases at a constant rate, it suggests a quadratic model. If the rate of change increases exponentially, it suggests an exponential model
step 3
Compare the differences between consecutive output values to determine the pattern
[3(i) Answer]
The function ff is best modeled by a [insert model type here] function.
step 1
To justify the model type, explain the observed pattern in the rate of change of f(x)f(x)
[3(ii) Answer]
The reason for choosing the [insert model type here] model is based on the [insert explanation of the pattern here].
Key Concept
Composition of functions and inverse functions
Explanation
To find h(x)h(x), we compose gg with ff. To find f1(x)f^{-1}(x), we look for the input that gives the desired output.
Key Concept
Solving equations and end behavior of rational functions
Explanation
To find where g(x)=5g(x) = 5, we solve the equation. The end behavior is found by analyzing the leading terms as xx approaches infinity.
Key Concept
Modeling functions based on rate of change
Explanation
The best model for f(x)f(x) is determined by the pattern of change in the output values as the input values increase.
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