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6. 设 XX 有连续的尾分布函数 G(x)=P(X>x)G(x)=P(X>x), 定义它的广义逆 G1(u):=inf{x:G(x)G^{-1}(u):=\inf \{x: G(x) \leq $u\} ...
Apr 8, 2024
6. 设 XX 有连续的尾分布函数 G(x)=P(X>x), 定义它的广义逆 G1(u):=inf{x:G(x)G^{-1}(u):=\inf \{x: G(x) \leq u};UU(0,1);gu\} ; U \sim U(0,1) ; g[0,1][0,1] 上的严格单调增函数, g(0)=0,g(1)=1g(0)=0, g(1)=1, 它的逆记为 g1g^{-1}; (1) 证明 G1(U)=dXG^{-1}(U) \stackrel{d}{=} X; (2) 求 G(X)G(X) 的分布; (3) 设 Y:=g(G(X))Y:=g(G(X)), 求 YY 的尾分布函数; (4) 试用 X,G1,g1X, G^{-1}, g^{-1} 构造随机变量 YY, 使得 YY 的尾分布函数为 gGg \circ G.
Solution by Steps
step 1
To prove G1(U)=dX G^{-1}(U) \stackrel{d}{=} X , we need to show that for any t t , P(G1(U)t)=P(Xt) P(G^{-1}(U) \leq t) = P(X \leq t)
step 2
Since UU(0,1) U \sim U(0,1) , for any t t , P(G1(U)t)=P(UG(t)) P(G^{-1}(U) \leq t) = P(U \leq G(t))
step 3
By definition of G G , G(t) = P(X > t) , so P(U \leq G(t)) = 1 - P(X > t) = P(X \leq t)
step 4
Therefore, G1(U)=dX G^{-1}(U) \stackrel{d}{=} X is proven
Answer
G1(U)=dX G^{-1}(U) \stackrel{d}{=} X is proven.
Key Concept
Quantile Function
Explanation
The quantile function G1 G^{-1} applied to a uniform random variable U U on (0,1) (0,1) yields a random variable with the same distribution as X X .
step 1
To find the distribution of G(X) G(X) , we calculate P(G(X)u) P(G(X) \leq u) for u[0,1] u \in [0,1]
step 2
By definition of G G , G(X)u G(X) \leq u implies P(X > x) \leq u where x=G1(u) x = G^{-1}(u)
step 3
Thus, P(G(X) \leq u) = P(X > G^{-1}(u)) = 1 - G(G^{-1}(u)) = 1 - u
step 4
The distribution of G(X) G(X) is uniform on [0,1] [0,1]
Answer
The distribution of G(X) G(X) is uniform on [0,1] [0,1] .
Key Concept
Distribution of a Transformed Random Variable
Explanation
The distribution of G(X) G(X) is found by evaluating the probability P(G(X)u) P(G(X) \leq u) and showing it is uniform.
step 1
To find the tail distribution function of Y=g(G(X)) Y = g(G(X)) , we calculate P(Y > y) for y[0,1] y \in [0,1]
step 2
Since g g is strictly increasing, P(Y > y) = P(g(G(X)) > y) = P(G(X) > g^{-1}(y))
step 3
Using the result from the previous question, P(G(X) > g^{-1}(y)) = 1 - P(G(X) \leq g^{-1}(y)) = g^{-1}(y)
step 4
The tail distribution function of Y Y is g1(y) g^{-1}(y)
Answer
The tail distribution function of Y Y is g1(y) g^{-1}(y) .
Key Concept
Tail Distribution Function
Explanation
The tail distribution function of a transformed random variable Y Y is found by evaluating P(Y > y) using the inverse function g1 g^{-1} .
step 1
To construct a random variable Y Y using X,G1,g1 X, G^{-1}, g^{-1} such that Y Y 's tail distribution function is gG g \circ G , we define Y=g(G(X)) Y = g(G(X))
step 2
From the previous steps, we know that Y=g(G(X)) Y = g(G(X)) has a tail distribution function g1(y) g^{-1}(y)
step 3
To match the tail distribution function gG g \circ G , we use the fact that g g is strictly increasing and g(0)=0,g(1)=1 g(0) = 0, g(1) = 1
step 4
Therefore, Y=g(G(X)) Y = g(G(X)) is the required construction
Answer
Y=g(G(X)) Y = g(G(X)) is the required construction.
Key Concept
Construction of a Random Variable
Explanation
The random variable Y Y is constructed using the composition of g g and G G applied to X X to achieve the desired tail distribution function.
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