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6. 设
X
X
X
有连续的尾分布函数
G
(
x
)
=
P
(
X
>
x
)
G(x)=P(X>x)
G
(
x
)
=
P
(
X
>
x
)
, 定义它的广义逆
G
−
1
(
u
)
:
=
inf
{
x
:
G
(
x
)
≤
G^{-1}(u):=\inf \{x: G(x) \leq
G
−
1
(
u
)
:=
in
f
{
x
:
G
(
x
)
≤
$u\} ...
Apr 8, 2024
6. 设
X
X
X
有连续的尾分布函数 G(x)=P(X>x), 定义它的广义逆
G
−
1
(
u
)
:
=
inf
{
x
:
G
(
x
)
≤
G^{-1}(u):=\inf \{x: G(x) \leq
G
−
1
(
u
)
:=
in
f
{
x
:
G
(
x
)
≤
u
}
;
U
∼
U
(
0
,
1
)
;
g
u\} ; U \sim U(0,1) ; g
u
}
;
U
∼
U
(
0
,
1
)
;
g
是
[
0
,
1
]
[0,1]
[
0
,
1
]
上的严格单调增函数,
g
(
0
)
=
0
,
g
(
1
)
=
1
g(0)=0, g(1)=1
g
(
0
)
=
0
,
g
(
1
)
=
1
, 它的逆记为
g
−
1
g^{-1}
g
−
1
; (1) 证明
G
−
1
(
U
)
=
d
X
G^{-1}(U) \stackrel{d}{=} X
G
−
1
(
U
)
=
d
X
; (2) 求
G
(
X
)
G(X)
G
(
X
)
的分布; (3) 设
Y
:
=
g
(
G
(
X
)
)
Y:=g(G(X))
Y
:=
g
(
G
(
X
))
, 求
Y
Y
Y
的尾分布函数; (4) 试用
X
,
G
−
1
,
g
−
1
X, G^{-1}, g^{-1}
X
,
G
−
1
,
g
−
1
构造随机变量
Y
Y
Y
, 使得
Y
Y
Y
的尾分布函数为
g
∘
G
g \circ G
g
∘
G
.
Solution by Steps
step 1
To prove
G
−
1
(
U
)
=
d
X
G^{-1}(U) \stackrel{d}{=} X
G
−
1
(
U
)
=
d
X
, we need to show that for any
t
t
t
,
P
(
G
−
1
(
U
)
≤
t
)
=
P
(
X
≤
t
)
P(G^{-1}(U) \leq t) = P(X \leq t)
P
(
G
−
1
(
U
)
≤
t
)
=
P
(
X
≤
t
)
step 2
Since
U
∼
U
(
0
,
1
)
U \sim U(0,1)
U
∼
U
(
0
,
1
)
, for any
t
t
t
,
P
(
G
−
1
(
U
)
≤
t
)
=
P
(
U
≤
G
(
t
)
)
P(G^{-1}(U) \leq t) = P(U \leq G(t))
P
(
G
−
1
(
U
)
≤
t
)
=
P
(
U
≤
G
(
t
))
step 3
By definition of
G
G
G
, G(t) = P(X > t) , so P(U \leq G(t)) = 1 - P(X > t) = P(X \leq t)
step 4
Therefore,
G
−
1
(
U
)
=
d
X
G^{-1}(U) \stackrel{d}{=} X
G
−
1
(
U
)
=
d
X
is proven
Answer
G
−
1
(
U
)
=
d
X
G^{-1}(U) \stackrel{d}{=} X
G
−
1
(
U
)
=
d
X
is proven.
Key Concept
Quantile Function
Explanation
The quantile function
G
−
1
G^{-1}
G
−
1
applied to a uniform random variable
U
U
U
on
(
0
,
1
)
(0,1)
(
0
,
1
)
yields a random variable with the same distribution as
X
X
X
.
step 1
To find the distribution of
G
(
X
)
G(X)
G
(
X
)
, we calculate
P
(
G
(
X
)
≤
u
)
P(G(X) \leq u)
P
(
G
(
X
)
≤
u
)
for
u
∈
[
0
,
1
]
u \in [0,1]
u
∈
[
0
,
1
]
step 2
By definition of
G
G
G
,
G
(
X
)
≤
u
G(X) \leq u
G
(
X
)
≤
u
implies P(X > x) \leq u where
x
=
G
−
1
(
u
)
x = G^{-1}(u)
x
=
G
−
1
(
u
)
step 3
Thus, P(G(X) \leq u) = P(X > G^{-1}(u)) = 1 - G(G^{-1}(u)) = 1 - u
step 4
The distribution of
G
(
X
)
G(X)
G
(
X
)
is uniform on
[
0
,
1
]
[0,1]
[
0
,
1
]
Answer
The distribution of
G
(
X
)
G(X)
G
(
X
)
is uniform on
[
0
,
1
]
[0,1]
[
0
,
1
]
.
Key Concept
Distribution of a Transformed Random Variable
Explanation
The distribution of
G
(
X
)
G(X)
G
(
X
)
is found by evaluating the probability
P
(
G
(
X
)
≤
u
)
P(G(X) \leq u)
P
(
G
(
X
)
≤
u
)
and showing it is uniform.
step 1
To find the tail distribution function of
Y
=
g
(
G
(
X
)
)
Y = g(G(X))
Y
=
g
(
G
(
X
))
, we calculate P(Y > y) for
y
∈
[
0
,
1
]
y \in [0,1]
y
∈
[
0
,
1
]
step 2
Since
g
g
g
is strictly increasing, P(Y > y) = P(g(G(X)) > y) = P(G(X) > g^{-1}(y))
step 3
Using the result from the previous question, P(G(X) > g^{-1}(y)) = 1 - P(G(X) \leq g^{-1}(y)) = g^{-1}(y)
step 4
The tail distribution function of
Y
Y
Y
is
g
−
1
(
y
)
g^{-1}(y)
g
−
1
(
y
)
Answer
The tail distribution function of
Y
Y
Y
is
g
−
1
(
y
)
g^{-1}(y)
g
−
1
(
y
)
.
Key Concept
Tail Distribution Function
Explanation
The tail distribution function of a transformed random variable
Y
Y
Y
is found by evaluating P(Y > y) using the inverse function
g
−
1
g^{-1}
g
−
1
.
step 1
To construct a random variable
Y
Y
Y
using
X
,
G
−
1
,
g
−
1
X, G^{-1}, g^{-1}
X
,
G
−
1
,
g
−
1
such that
Y
Y
Y
's tail distribution function is
g
∘
G
g \circ G
g
∘
G
, we define
Y
=
g
(
G
(
X
)
)
Y = g(G(X))
Y
=
g
(
G
(
X
))
step 2
From the previous steps, we know that
Y
=
g
(
G
(
X
)
)
Y = g(G(X))
Y
=
g
(
G
(
X
))
has a tail distribution function
g
−
1
(
y
)
g^{-1}(y)
g
−
1
(
y
)
step 3
To match the tail distribution function
g
∘
G
g \circ G
g
∘
G
, we use the fact that
g
g
g
is strictly increasing and
g
(
0
)
=
0
,
g
(
1
)
=
1
g(0) = 0, g(1) = 1
g
(
0
)
=
0
,
g
(
1
)
=
1
step 4
Therefore,
Y
=
g
(
G
(
X
)
)
Y = g(G(X))
Y
=
g
(
G
(
X
))
is the required construction
Answer
Y
=
g
(
G
(
X
)
)
Y = g(G(X))
Y
=
g
(
G
(
X
))
is the required construction.
Key Concept
Construction of a Random Variable
Explanation
The random variable
Y
Y
Y
is constructed using the composition of
g
g
g
and
G
G
G
applied to
X
X
X
to achieve the desired tail distribution function.
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