To solve the equation 2x−5=3x+1, we need to find a common base or use logarithms
step 2
Taking the logarithm of both sides of the equation, we get log(2x−5)=log(3x+1)
step 3
Applying the power rule of logarithms, we can simplify to (x−5)log(2)=(x+1)log(3)
step 4
Rearrange the equation to isolate terms with x on one side: xlog(2)−5log(2)=xlog(3)+log(3)
step 5
Group the x terms together and the constant terms together: x(log(2)−log(3))=5log(2)+log(3)
step 6
Solve for x by dividing both sides by (log(2)−log(3)): x=log(2)−log(3)5log(2)+log(3)
Answer
x=log(2)−log(3)5log(2)+log(3)
Key Concept
Solving Exponential Equations Using Logarithms
Explanation
To solve an equation where the variable is in an exponent, we can use logarithms to bring the variable down to a solvable level. By applying the power rule of logarithms, we can then isolate the variable and solve for it.