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12. A simple pendulum is put into oscillation on Earth, Pluto, Mars and Jupiter....
Jan 29, 2024
12. A simple pendulum is put into oscillation on Earth, Pluto, Mars and Jupiter. Given that their gravitational accelerations are 10 ms2,0.8 ms2,3.8 ms210 \mathrm{~ms}^{-2}, 0.8 \mathrm{~ms}^{-2}, 3.8 \mathrm{~ms}^{-2}, and 25.4 ms225.4 \mathrm{~ms}^{-2} respectively, on which celestial body will the simple pendulum oscillate the fastest? A Earth B Pluto C Mars D Jupiter
Solution by Steps
step 2
The period T T is inversely proportional to the square root of the gravitational acceleration g g . Therefore, the larger the value of g g , the smaller the period T T , meaning the pendulum oscillates faster
step 3
We compare the given gravitational accelerations: Earth (10 ms210 \mathrm{~ms}^{-2}), Pluto (0.8 ms20.8 \mathrm{~ms}^{-2}), Mars (3.8 ms23.8 \mathrm{~ms}^{-2}), and Jupiter (25.4 ms225.4 \mathrm{~ms}^{-2})
step 4
Since Jupiter has the highest gravitational acceleration (25.4 ms225.4 \mathrm{~ms}^{-2}), the pendulum will oscillate the fastest on Jupiter
D
Key Concept
Gravitational Acceleration and Pendulum Period
Explanation
The period of a simple pendulum is inversely proportional to the square root of the gravitational acceleration. The higher the gravitational acceleration, the faster the pendulum oscillates.
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