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10 In sports like bowling or golf, players often have a 'handicap' (h)(h). A han...
Oct 14, 2024
Solution by Steps
step 1
The domain of the function h(s)=0.9(220s)h(s) = 0.9(220 - s) is determined by the values of ss that make sense in the context of bowling scores. Since ss represents a bowler's average score, it must be less than or equal to 220. Therefore, the domain is s220s \leq 220. The domain can be expressed as (,220](-\infty, 220]
step 2
To find the inverse of the function h(s)h(s), we start with the equation h(s)=0.9(220s)h(s) = 0.9(220 - s). We will solve for ss in terms of hh. First, we set h=0.9(220s)h = 0.9(220 - s) and rearrange: s=220h0.9s = 220 - \frac{h}{0.9}. Thus, the inverse function is h1(h)=220h0.9h^{-1}(h) = 220 - \frac{h}{0.9}
step 3
To confirm the result graphically, we can plot both h(s)h(s) and its inverse h1(h)h^{-1}(h). The graph of the function and its inverse should be symmetric about the line y=xy = x. This confirms that the inverse is indeed a function
step 4
To find the average score for an opponent whose handicap is 15, we substitute h=15h = 15 into the inverse function: s=220150.9s = 220 - \frac{15}{0.9}. Calculating this gives s=22016.67203.33s = 220 - 16.67 \approx 203.33. Therefore, the average score for the opponent is approximately 203.33
Answer
The average score for an opponent whose handicap is 15 is approximately 203.33.
Key Concept
The concept of a handicap in sports allows for fair competition between players of different skill levels by adjusting scores.
Explanation
The handicap formula provides a way to calculate the adjusted score, and finding the inverse allows us to determine the original score based on the handicap. The domain restriction ensures that we only consider realistic bowling scores.
What is the range of the function h(s)=0.9(220s)h(s) = 0.9(220 - s) given its domain restrictions?
Solution by Steps
step 1
The domain of the function h(s)=0.9(220s)h(s) = 0.9(220 - s) is determined by the values of ss that make sense in the context of bowling scores. Since ss represents a bowler's average score, it must be less than or equal to 220. Therefore, the domain is s220s \leq 220. The domain can be expressed as (,220](-\infty, 220]
step 2
To find the inverse of the function, we start with h(s)=0.9(220s)h(s) = 0.9(220 - s). Setting h(s)=yh(s) = y, we have y=0.9(220s)y = 0.9(220 - s). Rearranging gives s=220y0.9s = 220 - \frac{y}{0.9}. Thus, the inverse function is h1(y)=220y0.9h^{-1}(y) = 220 - \frac{y}{0.9}
step 3
To confirm the result graphically, we can plot both h(s)h(s) and h1(y)h^{-1}(y). The graph of the inverse will reflect over the line y=xy = x, confirming that it is indeed a function
step 4
To find the average score for an opponent whose handicap is 15, we set h(s)=15h(s) = 15. Thus, 15=0.9(220s)15 = 0.9(220 - s). Solving for ss gives s=220150.9203.33s = 220 - \frac{15}{0.9} \approx 203.33
Answer
The average score for an opponent whose handicap is 15 is approximately 203.33.
Key Concept
The function h(s)h(s) represents the calculation of a bowler's handicap based on their average score.
Explanation
The domain is restricted to ensure that the average score is realistic within the context of bowling, and the inverse function allows us to determine the average score based on a given handicap.
Generated Graph
Solution by Steps
step 1
To find the inverse of the function f(x)=5x2f(x) = 5x - 2, we start by replacing f(x)f(x) with yy: y=5x2y = 5x - 2
step 2
Next, we solve for xx: y+2=5x    x=y+25y + 2 = 5x \implies x = \frac{y + 2}{5}
step 3
Thus, the inverse function is f1(y)=y+25f^{-1}(y) = \frac{y + 2}{5}. The domain of f(x)f(x) is all real numbers, so the range of f1(y)f^{-1}(y) is also all real numbers
step 4
For the function f(x)=712xf(x) = 7 - \frac{1}{2}x, we set y=712xy = 7 - \frac{1}{2}x
step 5
Solving for xx: y7=12x    x=2(y7)=2y+14y - 7 = -\frac{1}{2}x \implies x = -2(y - 7) = -2y + 14
step 6
The inverse function is f1(y)=2y+14f^{-1}(y) = -2y + 14. The domain of f(x)f(x) is all real numbers, so the range of f1(y)f^{-1}(y) is also all real numbers
step 7
For the function f(x)=x23f(x) = x^2 - 3, we restrict the domain to x0x \geq 0 to ensure the inverse is a function
step 8
Setting y=x23y = x^2 - 3, we solve for xx: y+3=x2    x=y+3y + 3 = x^2 \implies x = \sqrt{y + 3}
step 9
The inverse function is f1(y)=y+3f^{-1}(y) = \sqrt{y + 3} with the restricted domain y3y \geq -3
step 10
For the function f(x)=1x2f(x) = 1 - x^2, we restrict the domain to x1x \leq 1 to ensure the inverse is a function
step 11
Setting y=1x2y = 1 - x^2, we solve for xx: x2=1y    x=1yx^2 = 1 - y \implies x = -\sqrt{1 - y}
step 12
The inverse function is f1(y)=1yf^{-1}(y) = -\sqrt{1 - y} with the restricted domain y1y \leq 1
step 13
For the function f(x)=x+1xf(x) = \frac{x + 1}{x}, we restrict the domain to x > 0 to ensure the inverse is a function
step 14
Setting y=x+1xy = \frac{x + 1}{x}, we solve for xx: yx=x+1    x(y1)=1    x=1y1yx = x + 1 \implies x(y - 1) = 1 \implies x = \frac{1}{y - 1}
step 15
The inverse function is f1(y)=1y1f^{-1}(y) = \frac{1}{y - 1} with the restricted domain y1y \neq 1
step 16
For the function f(x)=(x2)2f(x) = (x - 2)^2, we restrict the domain to x2x \geq 2 to ensure the inverse is a function
step 17
Setting y=(x2)2y = (x - 2)^2, we solve for xx: x2=y    x=y+2x - 2 = \sqrt{y} \implies x = \sqrt{y} + 2
step 18
The inverse function is f1(y)=y+2f^{-1}(y) = \sqrt{y} + 2 with the restricted domain y0y \geq 0
Answer
The inverses of the functions are as follows: 1. f1(y)=y+25f^{-1}(y) = \frac{y + 2}{5} 2. f1(y)=2y+14f^{-1}(y) = -2y + 14 3. f1(y)=y+3f^{-1}(y) = \sqrt{y + 3} (restricted to y3y \geq -3) 4. f1(y)=1yf^{-1}(y) = -\sqrt{1 - y} (restricted to y1y \leq 1) 5. f1(y)=1y1f^{-1}(y) = \frac{1}{y - 1} (restricted to y1y \neq 1) 6. f1(y)=y+2f^{-1}(y) = \sqrt{y} + 2 (restricted to y0y \geq 0)
Key Concept
Finding the inverse of a function involves solving for the variable in terms of the output variable, and sometimes restricting the domain to ensure the inverse is also a function.
Explanation
The inverses were derived by algebraically manipulating the original functions, and domain restrictions were applied where necessary to maintain the function property of the inverses.
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