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1. 不论 mm 取什么实数, 点 A(m+1,m2+2m−5)A\left(m+1, m^{2}+2 m-5\right) 都在菓函数图像上, 若 B(a,b)B(a, b) 也是该函数圆...
Mar 9, 2024
1. 不论 mm 取什么实数, 点 A(m+1,m2+2m−5)A\left(m+1, m^{2}+2 m-5\right) 都在菓函数图像上, 若 B(a,b)B(a, b) 也是该函数圆像上的点, 则 a2−b=\mathrm{a}^{2}-\mathrm{b}=
Solution by Steps
step 1
To find the value of a2−b a^2 - b for point B(a,b) B(a, b) on the function's graph, we use the given equation from the asksia-ll calculation list
step 2
The equation from the asksia-ll calculation list is a2−b=(m+1)2−(m2+2m−5) a^2 - b = (m + 1)^2 - (m^2 + 2m - 5)
step 3
We simplify the right side of the equation by expanding (m+1)2 (m + 1)^2 to m2+2m+1 m^2 + 2m + 1
step 4
Subtracting m2+2m−5 m^2 + 2m - 5 from m2+2m+1 m^2 + 2m + 1 gives us 6 6
step 5
Therefore, a2−b=6 a^2 - b = 6
Answer
a2−b=6 a^2 - b = 6
Key Concept
Simplifying an equation
Explanation
The value of a2−b a^2 - b is found by simplifying the given equation, which results in a constant value of 6, regardless of the value of m m .
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