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1 point) Find a function ff and a number aa such that \[ 2+\int_{a}^{x} \fra...
Feb 1, 2024
1 point) Find a function ff and a number aa such that 2+axf(t)t2dt=6x3 2+\int_{a}^{x} \frac{f(t)}{t^{2}} d t=6 x^{-3}
Solution by Steps
step 1
Given the integral equation 2+axf(t)t2dt=6x32+\int_{a}^{x} \frac{f(t)}{t^{2}} dt=6 x^{-3}, we want to isolate the integral on one side
step 2
Subtract 2 from both sides to get axf(t)t2dt=6x32\int_{a}^{x} \frac{f(t)}{t^{2}} dt=6 x^{-3} - 2
step 3
From the asksia-ll calculation list, we have two possible expressions for the integral: 6/x326/x^3 - 2 and (2(x33))/x3-(2 (x^3 - 3))/x^3
step 4
Both expressions are equal to the integral, so we can set them equal to each other: 6/x32=(2(x33))/x36/x^3 - 2 = -(2 (x^3 - 3))/x^3
step 5
Simplify the right side to get 6/x32=2+6/x36/x^3 - 2 = -2 + 6/x^3
step 6
This confirms that the integral of f(t)/t2f(t)/t^2 from aa to xx is indeed 6/x326/x^3 - 2
step 7
To find f(t)f(t), we differentiate both sides of the equation with respect to xx, using the Fundamental Theorem of Calculus, Part 1
step 8
Differentiating 6/x326/x^3 - 2 with respect to xx gives f(x)/x2=18/x4f(x)/x^2 = -18/x^4
step 9
Multiply both sides by x2x^2 to solve for f(x)f(x): f(x)=18/x2f(x) = -18/x^2
step 10
Since the integral is from aa to xx, and we have no initial condition to find aa, we can choose aa to be any value that makes the integral valid. Let's choose a=1a = 1 for simplicity
Answer
f(x)=18/x2f(x) = -18/x^2 and a=1a = 1
Key Concept
Isolating the integral and differentiating to find the function
Explanation
We isolated the integral from the given equation and then differentiated both sides with respect to xx to find the function f(x)f(x). We chose a=1a = 1 because the problem does not provide specific conditions to determine aa.
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