1 point) Find a function f and a number a such that
\[
2+\int_{a}^{x} \fra...
Feb 1, 2024
1 point) Find a function f and a number a such that
2+∫axt2f(t)dt=6x−3
Solution by Steps
step 1
Given the integral equation 2+∫axt2f(t)dt=6x−3, we want to isolate the integral on one side
step 2
Subtract 2 from both sides to get ∫axt2f(t)dt=6x−3−2
step 3
From the asksia-ll calculation list, we have two possible expressions for the integral: 6/x3−2 and −(2(x3−3))/x3
step 4
Both expressions are equal to the integral, so we can set them equal to each other: 6/x3−2=−(2(x3−3))/x3
step 5
Simplify the right side to get 6/x3−2=−2+6/x3
step 6
This confirms that the integral of f(t)/t2 from a to x is indeed 6/x3−2
step 7
To find f(t), we differentiate both sides of the equation with respect to x, using the Fundamental Theorem of Calculus, Part 1
step 8
Differentiating 6/x3−2 with respect to x gives f(x)/x2=−18/x4
step 9
Multiply both sides by x2 to solve for f(x): f(x)=−18/x2
step 10
Since the integral is from a to x, and we have no initial condition to find a, we can choose a to be any value that makes the integral valid. Let's choose a=1 for simplicity
Answer
f(x)=−18/x2 and a=1
Key Concept
Isolating the integral and differentiating to find the function
Explanation
We isolated the integral from the given equation and then differentiated both sides with respect to x to find the function f(x). We chose a=1 because the problem does not provide specific conditions to determine a.